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3 years ago

Please help!!!!

Chemistry

1 answer:

guapka [62]3 years ago

3 0

Explanation:

₁₄Si 1s²2s²2p⁶3s²3p².

Principal quantum number (n=3) have four electrons (3s²3p²).

2) ₁₉K 1s²2s²2p⁶3s²3p⁶4s¹.

Azimuthal quantum number (l=o) have seven electrons (1s²2s²3s²4s¹).

3) ₈₀Hg [Xe] 4f¹⁴5d¹⁰6s².

Principal quantum number (n=4) have thirty-two electrons (4s²4p⁶4d¹⁰4f¹⁴).

The principal quantum number is one of four quantum numbers which are assigned to each electron in an atom to describe that electron's state.

The azimuthal quantum number is a quantum number for an atomic orbital that determines its orbital angular momentum and describes the shape of the orbital.

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What is the molarity of a solution of 10% by mass cadmium sulfate, CdSO4 (molar mass = 208.46 g/mol) by mass? The density of the

Gekata [30.6K]

Answer:

a. 0.528 M ..

Explanation:

Hello!

In this case, since the given by-mass percent can be written as:

$\frac{10gCdSO_4}{100g\ sol}$

By using the density and molar mass of the solute, cadmium sulfate, we can compute the molarity, by also making sure we convert from mL to L of solution:

$M=\frac{10gCdSO_4}{100g\ sol}*\frac{1molCdSO_4}{208.46gCdSO_4} *\frac{1.10g\ sol}{1mL\ sol} *\frac{1000mL\ sol}{1L\ sol} \\\\M=0.528M$

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3 years ago

A hot air balloon filled with 1.27x10^6L of an ideal gas on a cool morning of 11 degrees C. the air is heated to 105 degrees C.

Elenna [48]

Answer:

New volume = $1.69\times 10^6$ L

Explanation:

Using Charle's law

$\frac {V_1}{T_1}=\frac {V_2}{T_2}$

Given ,

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V₂ = ?

T₁ = 11 °C

T₂ = 105 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (11 + 273.15) K = 284.15 K

T₂ = (105 + 273.15) K = 378.15 K

Using above equation as:

$\frac{1.27\times 10^6}{284.15}=\frac{V_2}{378.15}$

$V_2=\frac{1.27\times 10^6\cdot \:378.15}{284.15}$

New volume = $1.69\times 10^6$ L

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4 years ago

If the volume of a solid is 100 cm3 and its mass is 400 g, what is its density?

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Under these circumstances, Its density is 4 grams per cm3

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4 years ago

A flask contains 5.0g of neon gas at a temperature of 35°C. The pressure gauge indicates 0.37atm inside the flask. What is the v

DaniilM [7]

Answer:

The volume of the neon gas is 17.07 L.

Explanation:

The ideal gas equation describes the relationship among the four variables P, V, T, and n. An ideal gas is a hypothetical gas whose pressure-volume-temperature behavior can be completely accounted for by the ideal gas equation.

In order to calculate the volume, first we need to convert the grams of neon to moles:

28.18 g Ne ------ 1 mol Ne

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3 years ago

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Answer:

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DATA

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3 years ago