<span>it fairly is going to attain a speed of 24 m/s in a 2d, yet between t = 0 and t = a million, it fairly is not any longer vacationing at that speed, yet at slower speeds. it fairly is 12 meters. ?D = [ ( a?T^2 + 2?Tv_i ) ] / 2 the place: ?D = displacement a = acceleration ?T = elapsed time v_i = preliminary speed ?D = [ ( 24m/s^2 • 1s • 1s + 2 • 1s • 0m/s ) ] / 2 ?D = 24 / 2 ?D = 12m</span>
Answer:
The time it takes the stone to reach the bottom of the cliff is approximately 4.293 s
Explanation:
The given parameters are;
The height of the cliff, h = 90.4 m
The direction in which the stone is thrown = Horizontally
The speed of the stone in the horizontal direction = 10 m/s
The time, t, it takes the stone to reach the bottom of the cliff is given by the equation for free fall as follows;
h = 1/2 × g × t²
Where;
g = The acceleration due to gravity = 9.81 m/s²
Substituting the values gives;
90.4 = 1/2 × 9.81 × t²
t² = 90.4/(1/2 × 9.81) ≈ 18.43 s²
t = √18.43 ≈ 4.293 s
The time it takes the stone to reach the bottom of the cliff is t ≈ 4.293 s.