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yKpoI14uk [10]
3 years ago
11

The concentration of iodide ions in a saturated solution of lead (ii) iodide is __________ m. the solubility product constant of

pbi2 is 1.4 x 10-8.
Chemistry
1 answer:
Allisa [31]3 years ago
3 0
When PbI₂ dissolves, it dissociates as follows
PbI₂ --> Pb²⁺ + 2I⁻
Molar solubility is the number of moles of salt that can be dissolved in 1 L of solution 
If molar solubility of PbI₂ is x , then molar solubility of Pb²⁺ is x and I⁻ is 2x .
ksp is solubility product constant. 
ksp = [Pb²⁺][I⁻]²
ksp = [x][2x]²
ksp = 4x³
4x³ = 1.4 x 10⁻⁸
x³ = 0.35 x 10⁻⁸
x = 1.51 x 10⁻³ M
since molar solubility of I⁻ is 2x , then molar solubility of I⁻ is 3.03 x 10⁻³ M 
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