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fredd [130]
3 years ago
15

The helicopter in the drawing is moving horizontally to the right at a constant velocity. The weight of the helicopter is W=4250

0 N. The lift force L generated by the rotating blade makes an angle of 21.0° with respect to the vertical. (a) What is the magnitude of the lift force? (b) Determine the magnitude of the air resistance R that opposes the motion.
Physics
1 answer:
Rom4ik [11]3 years ago
3 0

Answer: A) 45503 N b) 16290 N

Explanation:

A)

L = W / cos 21 = 42500 / cos 21 = 45503 N

B)

R = L sin 21 = 45503 x sin 21 = 16290N

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Explanation:

From the question we are told that

   The initial pressure is P_1  =  11.2\ a.t.m

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Let the first volume be  V_1 Then the final volume will be  2 V_1

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Here r is the radius of the molecules which is  mathematically represented as

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Where C_p \  and\   C_v are the molar specific heat of a gas at constant pressure and  the molar specific heat of a gas at constant volume with values

     C_p=7 \  and\   C_v=5

=>   r =  \frac{7}{5}

=>  11.2*( V_1 ^{\frac{7}{5} } ) =  P_2  *  (2 V_1 ^{\frac{7}{5} } )

=>   P_2  =  [\frac{1}{2} ]^{\frac{7}{5} } * 11.2

=>  P_2  =  4.25 \ a.t.m

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