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fredd [130]
3 years ago
15

The helicopter in the drawing is moving horizontally to the right at a constant velocity. The weight of the helicopter is W=4250

0 N. The lift force L generated by the rotating blade makes an angle of 21.0° with respect to the vertical. (a) What is the magnitude of the lift force? (b) Determine the magnitude of the air resistance R that opposes the motion.
Physics
1 answer:
Rom4ik [11]3 years ago
3 0

Answer: A) 45503 N b) 16290 N

Explanation:

A)

L = W / cos 21 = 42500 / cos 21 = 45503 N

B)

R = L sin 21 = 45503 x sin 21 = 16290N

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\to M_1V_1+m_2v_2=M_1U_1+m_2u_2\\\\\to (10^{-2} kg) V_1 +0 = (10^{-2} kg)(2000 \frac{m}{s}) + (4 \ kg)(-4.2 \frac{m}{s}) \\\\\ \to 10^{-2} v_1 = 20 -16.8\\\\

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The kinetic energy of the bullet in its emerges from the block

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