Answer:
a) V = 6.25 m/s
b) d = 4.6 m
Explanation:
a) <u>The pelican's initial speed is equal to the horizontal speed of the fish</u>. So we can calculate Vx of the fish knowing the fact that it travelled 8.0 m, using the formula for an <em>Uniformly Accelerated Motion</em> (because the fish is freefalling) to calculate the time the fish was falling:
D(t) = 0.5*a*t² + V₀*t + e₀
In this case, V₀ and e₀ are zero, a is gravity's acceleration and D(t) is 8.0 m
8.0 m = 0.5 * 9.81m/s² * t²
t² = 1.63 s²
t = 1.28 s
Thus Vx of the fish is:
8.0 m / 1.28 s = 6.25 m/s
<u>And that's the same initial speed of the pelican.</u>
b) The pelican is traveling at the same speed, so Vx of the fish remains the same, 6.25 m/s. First we calculate the time again:
D(t) = 0.5*a*t²
2.7 m = 0.5 * 9.81m/s² * t²
t² = 0.55 s²
t = 0.74 s
Now we use the formula V = d/t and solve for t:
6.25 m/s = d / 0.74 s
d = 4.6m
The entire electromagnetic spectrum, from the lowest to the highest frequency (longest to shortest wavelength), includes all radio waves (e.g., commercial radio and television, microwaves, radar), infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays.
False, There is other things aswell
Answer:
250 kg/m3
Explanation:
The total volume of the raft is length times width times height
V = lwh = 2 * 3 * 0.5 = 3 m cubed
The volume of the raft that is submerged in water is 1/4 of total volume
3 /4 = 0.75 m cubed
Let water density = 1000 kg/m cubed and g = 10 m/s2
The buoyant force is equal to the weight of water displaced by the raft
F = 0.75 * 1000 * 10 = 7500 N
This force is balanced by the raft weight, so the weight of the raft is also 7500N
Mass of raft is 7500 / g = 7500 / 10 = 750 kg
Raft density is mass divided by volume = 750 / 3 = 250 kg/m3
They are both the waste of the sea and land
Answer:
The difference between the velocity graph made walking at a steady rate means that its the same value in time, that means there's no slope on the graph, so its acceleration is 0
On the other hand, if the velocity is increasing with time, the slope of the graph becomes positive, which means that the acceleration of the particle is positive.
