Ask question

Ask question

All categories

adelina 88 [10]

2 years ago

11

A force of 20 N is exerted by an electric field on a test charge of 8.0 x 10² C at a point, P. What is the electric field streng

th
at point P?
0.004 N/C
Ob
1.6 N/C
Oc
160 N/C
Od
250 N/C

1 answer:

kenny6666 [7]2 years ago

5 0

Answer:

the answer is equal to 1.6N/C

You might be interested in

The small currents in axons corresponding to nerve impulses produce measurable magnetic fields. a typical axon carries a peak cu

Gemiola [76]

Answer:

$6.66\cdot 10^{-12}T$

Explanation:

The magnetic field produced by a current-carrying wire is given by

$B=\frac{\mu_0 I}{2\pi r}$

where

$\mu_0$ is the vacuum permeability

I is the current

r is the distance from the wire

In this problem we have

$I=0.040 \mu A=4\cdot 10^{-8}A$

r = 1.2 mm = 0.0012 m

So the magnetic field strength is

$B=\frac{(4\pi \cdot 10^{-7} H/m)(4\cdot 10^{-8}A)}{2\pi (0.0012 m)}=6.66\cdot 10^{-12}T$

5 0

3 years ago

Which type of mixture is air explain

igor_vitrenko [27]

Answer:Three elements make up over 99.9 percent of the composition of dry air: these are nitrogen, oxygen, and argon.

Explanation:

7 0

3 years ago

Read 2 more answers

How much time would it take for an airplane to reach its destination if it traveled at an average velocity of 820 km/hr NE for a

Vladimir79 [104]

Answer:

Time, t = 6.34 hours.

Explanation:

Velocity can be defined as the rate of change in displacement (distance) with time. Velocity is a vector quantity and as such it has both magnitude and direction.

Mathematically, velocity is given by the equation;

$Velocity = \frac{displacement}{time}$

Therefore, making time the subject of formula;

$Time = \frac{displacement}{velocity}$

Given the following data;

Displacement = 5200km

Average velocity = 820km/hr

Substituting into the equation, we have;

$Time = \frac{5200}{820}$

Time = 6.34 hours.

<em>Hence, it would take 6.34 hours for the airplane to reach its destination. </em>

5 0

3 years ago

A cork has weight mg and density 25% of water’s density. A string is tied around the cork and attached to the bottom of a water-

yuradex [85]

Answer:

Explanation:

Given

Density of Cork $\rho _c=0.25\rho _{water}$

Considering V be the volume of Cork

Buoyant Force will be acting Upward and Weight is acting Downward along with T

Since density of water is more than cork therefore Cork will try to escape out of water but due to tension it will not

we can write as

$\rho _{water}Vg-\rho _Cvg-T=0$

where T=tension

Thus Tension T is

$T=Vg(\rho _{water}-\rho _c)$

Taking $\rho _c$ common

$T=\rho _cVg(\frac{\rho _{water}}{\rho _c}-1)$

$T=mg(\frac{\rho _{water}}{\rho _c}-1)$

$T=mg(4-1)$

$T=3mg$

4 0

3 years ago

A racquet ball with mass m = 0.221 kg is moving toward the wall at v = 13.9 m/s and at an angle of θ = 25° with respect to the h

Salsk061 [2.6K]

Answer:

1) 3.07kgm/s

2) 5.56kgm/s

3) 76.16N

4) 4.33kgm/s

5) 0.57s

6) -8.66J

Explanation:

Given

m = 0.221kg

v = 13.9m/s

θ = 25°

t = 0.073s

1) to get the magnitude of the initial momentum is the racquet ball. We use the formula,

P(i) = mv(i)

P(i) = 0.221 * 13.9

P(i) = 3.07kgm/s

2) Magnitude of the change in momentum of the ball,

P(i,x) = P(i) cos θ

P(i,x) = 3.07 * cos25

P(i,x) = 3.07 * 0.9063

P(i,x) = 2.78

ΔP = 2P(i,x)

ΔP = 2 * 2.78 = 5.56kgm/s

3) magnitude of the average force exerted by the wall,

F(ave) = ΔP/Δt

F(ave) = 5.56/0.073

F(ave) = 76.16N

4) ΔP(z) = mv(f) - mv(i)

ΔP(z) = 0.221*-7.8 - 0.221*11.8

ΔP(z) = -1.72 - 2.61

ΔP(z) = 4.33kgm/s

5) F(ave) = ΔP/Δt

Δt = ΔP/F(ave)

Δt = 4.33 / 76.16

Δt = 0.57s

6) KE(i) = 0.5mv(i)²

KE(f) = 0.5mv(f)²

ΔKE = 0.5m[v(f)² - v(i)²]

ΔKE = 0.5 * 0.221 [(-7.8)² - 11.8²]

ΔKE = 0.1105 ( 60.84 - 139.24 )

ΔKE = 0.1105 * -78.4

ΔKE = -8.66J

6 0

3 years ago