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Oksi-84 [34.3K]
3 years ago
8

99 POINT QUESTION PLUS BRAINLIEST!!!

Physics
2 answers:
balu736 [363]3 years ago
7 0
The answer should be (C.) 60m
ollegr [7]3 years ago
6 0
Well i cant <span>explain it as well as i would like, if i did it would make no sens, but the answer should be (C.) 60m. but i`m only 95% sure its the answer. i hope this helps!</span>
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A typical atomic polarizability is 1 × 10-40 (C·m)/(N/C). If the q in p = qs is equal to the proton charge e, what charge separa
Alenkasestr [34]

Answer:

s = 6.25 10⁻²² m

Explanation:

Polarizability is the separation of electric charges in a structure, in the case of the atom it is the result of the separation of positive charges in the nucleus and the electrons in their orbits, macroscopically it is approximated by

                p = q s

               s = p / q

let's calculate

              s = 1 10⁻⁴⁰ / 1.6 10⁻¹⁹

              s = 0.625 10⁻²¹ m

              s = 6.25 10⁻²² m

We see that the result is much smaller than the size of the atom, therefore this simplistic model cannot be taken to an atomic scale.

6 0
3 years ago
Estimate and determine the order of magnitude of the circumference of the Earth in miles and the speed of a sailboat in miles pe
solmaris [256]

Answer:

= 1000 hours

Explanation:

Earth's circumference is 10⁴ mile

speed of a sailboat is 10¹ mile/hour

distance = speed × time

10⁴ = 10¹  × t

t = 10⁴ / 10¹

t = 10³

= 1000 hours

4 0
3 years ago
Suppose the U.S. national debt is about $15 trillion. If payments were made at the rate of $1,500 per second, how many years wou
Delvig [45]

Answer:

This question has already been answered.

Explanation:

brainly.com/question/13542582

3 0
3 years ago
How is the frequency of an electromagnetic wave related to energy
aivan3 [116]

Answer: The energy carried by an electromagnetic wave is proportional to the frequency of the wave.  

Explanation:

Electromagnetic waves that are of higher energy than visible light (higher frequency, shorter wavelength) include ultraviolet light, X-rays, and gamma rays.

7 0
3 years ago
I need help with these questions.
strojnjashka [21]

I'll go ahead and answer the ones here without an answer. For reference, the half-life formula is <em>final amount = original amount(1/2)^(time/half-life)</em>

<em />

4) 12.5g

x = 100(1/2)^(63/21)

5) 50g

3.125 = x(1/2)^(0.1/0.025)

6) 500g

x = 4000(1/2)^(525/175)

7) 0.24g

0.06 = x(1/2)^(11430/5730)

8) 125g

x = 1000(1/2)^(17100/5700)

Hope this helps! :)

4 0
3 years ago
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