Answer:
4.167
4.83871 cm
Explanation:
u = Object distance
v = Image distance = 25 cm
f = Focal length = 6 cm
Angular magnification is given by
The angular magnification of the lens is 4.167
Lens equation
The closest distance by which the object can be examined is 4.83871 cm
Answer:
vf = 14.2176 m/s
Explanation:
Given
m = 4 Kg
viy = 7.00 ĵ m/s
Fx = 11.0 î N
t = 4.5 s
vf = ?
Using the Impulse - Momentum Theorem, we have
F*Δt = m*Δv ⇒ F*Δt = m*(vf - vi)
⇒ vf = (F*Δt + m*vi) / m
⇒ vf = (F*Δt + m*vi) / m
For <em>x-component</em>
⇒ vfx = (Fx*Δt + m*vix) / m = (11 N*4.5 s + 4 Kg*0 m/s) / (4 Kg)
⇒ vfx = 12.375 î m/s
For <em>y-component</em>
⇒ vfy = (Fy*Δt + m*viy) / m = (0 N*4.5 s + 4 Kg*7 m/s) / (4 Kg)
⇒ vfy = 7 ĵ m/s
Finally:
vf = √(vfx² + vfy²)
⇒ vf = √((12.375 m/s)² + (7 m/s)²)
⇒ vf = 14.2176 m/s
Answer:
0.2s
Explanation:
SO for the dolphin to hear its echo, the sound wave must travel a distance twice as much as the displacement between the dolphin and the ocean floor. So d = 154 * 2 = 308 m
Since the speed of sound in ocean floor is v = 1533m/s we can find out the time by dividing the distance d by the speed of sound
t = d / v = 308 / 1533 = 0.2s
Answer:
Explanation:
Angular speed of the motion ( SHM )
ω = √k/m
= √(580/.23 )
= 50.20 radian /s
a ) Rate of doing work
= power = force x velocity
At the equilibrium position force becomes zero so
rate of doing work is zero.
b )
If a be the amplitude
1/2 k a² = 170
a = .7655 m
kinetic energy at equilibrium = 1/ 2 m v₀²
1/ 2 m v₀² = 170
.5 x 23 v₀² = 170
v₀ = 3.84 m /s which is the maximum velocity.
Given x = .66 where rate of doing work is to be calculated.
Force at x = ω² x
= 50.20² x .66 =
= 1663.22 N
Velocity v = v₀ √( a² - x² )
= 3.84 √( .7655² - .66 )
= 3.84 x .387
= 1.486 m/s
power = force x velocity
= 1663.22 x 1.486
= 2471.55 W .
20 joule is your answer
Answer:
here
mass m =100kg
distance d=50m
acceleration due to gravity a =10m/s²
work =force×displacement
= ma/d=100×10/50=20joule
