All categories

3 years ago

99 POINT QUESTION PLUS BRAINLIEST!!!

Physics

2 answers:

balu736 [363]3 years ago

7 0

The answer should be (C.) 60m

ollegr [7]3 years ago

6 0

Well i cant <span>explain it as well as i would like, if i did it would make no sens, but the answer should be (C.) 60m. but i`m only 95% sure its the answer. i hope this helps!</span>

You might be interested in

HELPPPPP ASAP WILL GIVE brainly to correct answer

viva [34]

Answer:

Option d

Plate tectonics i think but im not sure

3 0

3 years ago

Read 2 more answers

Name the processes of going (a) from a solid to a gas and (b) from a gas to a solid.

marissa [1.9K]

The answer to the first one is sublimation.

8 0

3 years ago

A 290 gg bird flying along at 6.2 m/sm/s sees a 9.0 gg insect heading straight toward it with a speed of 34 m/sm/s (as measured

Murrr4er [49]

Answer:

The bird's speed immediately after swallowing is 4.98 m/s.

Explanation:

Given that,

Mass of bird = 290 g

Speed = 6.2 m/s

Mass of sees = 9.0 g

Speed = 34 m/s

We need to calculate the bird's speed immediately after swallowing

Using conservation of momentum

$m_{1}v_{1}+m_{2}v_{2}=(m_{1}+m_{2})v_{3}$

Put the value into the formula

$0.290\times6.2+0.009\times(-34)=(0.290+0.009)\times v_{3}$

$v_{3}=\dfrac{0.290\times6.2-0.009\times34}{(0.290+0.009)}$

$v_{3}=4.98\ m/s$

Hence, The bird's speed immediately after swallowing is 4.98 m/s.

6 0

3 years ago

A weather balloon is designed to expand to a maximum radius of 21 m at its working altitude, where the air pressure is 0.030 atm

dezoksy [38]

Answer:

7.65 m

Explanation:

$P_1$ = Initial pressure = 0.03 atm

$P_2$ = Final pressure = 1 atm

$r_1$ = Inital radius = 21 m

$V_1$ = Intial volume of gas = $\frac{4}{3}\pi r_1^3$

$V_2$ = Final volume of gas = $\frac{4}{3}\pi r_2^3$

$T_1$ = Initial temperature = 200 K

$T_2$ = Final temperature = 323 K

From ideal gas law we have

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}\\\Rightarrow \frac{P_1\frac{4}{3}\pi r_1^3}{T_1}=\frac{P_2\frac{4}{3}\pi r_2^3}{T_2}\\\Rightarrow \frac{P_1 r_1^3}{T_1}=\frac{P_2r_2^3}{T_2}\\\Rightarrow r_2=\frac{P_1r_1^3T_2}{T_1P_2}\\\Rightarrow r_2=\left(\frac{0.03\times 21^3\times 323}{200\times 1}\right)^{\frac{1}{3}}\\\Rightarrow r_2=7.65\ m$

The radius at liftoff is 7.65 m

7 0

4 years ago

The reactive force developed by a jet engine to push an airplane forward is called thrust, and the thrust developed by the engin

finlep [7]

The value of the thrust developed by the engine of a boeing 777 in N and Kgf are ;

i) 376616N

ii) 38430Kgf

<h3>What is force?</h3>

Force is a push or a pull. The reactive force always serve to balance the applied force. We are here asked to convert the the thrust developed by the engine of a boeing 777 which is about 85400 lbf to the following units;

i) N

ii)kgf

Thus;

1 Ib = 0.45 Kg

1 lbf = 0.45 Kg * 9.8 m/s^2 = 4.41 N

We know that;

1 lbf = 4.41 N

85400 lbf = 85400 lbf. * 4.41 N/1 lbf

= 376616N

Again;

1 lbf = 0.45 Kgf

85400 lbf = 85400 lbf * 0.45 Kgf/1 lbf

= 38430Kgf

Learn more about force:brainly.com/question/13191643

#SPJ1

3 0

1 year ago