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seraphim [82]
3 years ago
6

Write a scientific question that is specific and testable. Jack and Jill when up a hill to fetch a pail of water. Once they got

to the well where was no pail. All they found was a stopwatch and nine rocks (the exact same size). What is a scientific question Jack and Jill could ask using the items they found???
Physics
1 answer:
Naya [18.7K]3 years ago
3 0

The scientific method consists of making an observation, ask a question, formulate hypothesis, predict, test, iterate

The scientific question that can be asked is; <u>What is the </u><u>depth of the well</u>

<u />

The reason why the above question is appropriate is as follows:

The items Jack and Jill found at the well

  • No pail
  • A stopwatch
  • Nine equal sized rocks

The information they can get using what they found are;

The time it takes the rock to reach the water surface in the well

The depth of the well

The well's depth, <em>h</em>, is given using the equation of free fall, as follows;

h = \dfrac{1}{2} \cdot g \cdot t^2

Where;

g ≈ Acceleration due to gravity ≈ 9.81 m/s²

By recording the time each rock takes to reach the water surface in the well, the average depth of the well, h_{ave}, can be found by finding the average of the 9 calculated values for <em>h</em> using the 9 stones

Therefore;

The scientific question that is specific and testable is <u>how </u><u>deep </u><u>is the </u><u>well</u><u>, or what is the well's depth</u>

Learn more about scientific method here:

brainly.com/question/13096299

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Which statement is true about the law of conservation of energy for an object released from a certain height above the ground
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4 years ago
An ocean thermal energy conversion system is being proposed for electric power generation. Such a system is based on the standar
defon

Answer:

Explanation:

Dear Student, this question is incomplete, and to attempt this question, we have attached the complete copy of the question in the image below. Please, Kindly refer to it when going through the solution to the question.

To objective is to find the:

(i) required heat exchanger area.

(ii) flow rate to be maintained in the evaporator.

Given that:

water temperature = 300 K

At a reasonable depth, the water is cold and its temperature = 280 K

The power output W = 2 MW

Efficiency \zeta = 3%

where;

\zeta = \dfrac{W_{out}}{Q_{supplied }}

Q_{supplied } = \dfrac{2}{0.03} \ MW

Q_{supplied } = 66.66 \ MW

However, from the evaporator, the heat transfer Q can be determined by using the formula:

Q = UA(L MTD)

where;

LMTD = \dfrac{\Delta T_1 - \Delta T_2}{In (\dfrac{\Delta T_1}{\Delta T_2} )}

Also;

\Delta T_1 = T_{h_{in}}- T_{c_{out}} \\ \\ \Delta T_1 = 300 -290 \\ \\ \Delta T_1 = 10 \ K

\Delta T_2 = T_{h_{in}}- T_{c_{out}} \\ \\ \Delta T_2 = 292 -290 \\ \\ \Delta T_2 = 2\ K

LMTD = \dfrac{10 -2}{In (\dfrac{10}{2} )}

LMTD = \dfrac{8}{In (5)}

LMTD = 4.97

Thus, the required heat exchanger area A is calculated by using the formula:

Q_H = UA (LMTD)

where;

U = overall heat coefficient given as 1200 W/m².K

66.667 \times 10^6 = 1200 \times A \times 4.97 \\ \\  A= \dfrac{66.667 \times 10^6}{1200 \times 4.97} \\ \\  \mathbf{A = 11178.236 \ m^2}

The mass flow rate:

Q_{H} = mC_p(T_{in} -T_{out} )  \\ \\  66.667 \times 10^6= m \times 4.18 (300 -292) \\ \\ m = \dfrac{  66.667 \times 10^6}{4.18 \times 8} \\ \\  \mathbf{m = 1993630.383 \ kg/s}

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Answer:solid

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