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diamong [38]
3 years ago
11

Calculate the amount of copper (in moles) in a 45.2 g pure copper sheet

Chemistry
1 answer:
tangare [24]3 years ago
8 0

Answer:

0.712 mol

Explanation:

The easiest way to do this is to use a proportion.

1 mol of copper = 63.5 grams (check this using your periodic table).

x mol of copper = 45.2 grams

1/x = 63.5 / 45.2              Cross multiply

63.5 x = 1 * 45.2              Divide by 63.5

x = 45.2/63.5

x = 0.712 mol                   Answer to 3 sig digs

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Car manufacturers are developing engines that use H₂ as fuel. In Iceland, Sweden, and other parts of Scandinavia, where hydroele
weeeeeb [17]

If the coulombs are supplied at 1.44 V, then 4.766 × 10¹¹ joules are produced.

(a) The reaction is

2H₂O + 2e⁻ → H₂ + 2OH⁻

According to the reaction, 2 moles of electrons flow per mole of reaction,

(b) Given

T = 25°C

Change Celsius into Kelvin

T = 25°C

   = (25 + 273 ) K

   = 298 K

<h3>What is Ideal Gas Law ?</h3>

It is expressed as

PV = nRT

Hence ,

n = \frac{PV}{RT}

   = \frac{(12)(3.5.10^{6} )}{(0.082057)(298)}

   = 1.7176 ×10⁶ mole

Now, From the given reaction we can say that ,1 mole of H₂  is produced by 2 moles of electron

Hence, 1.7176 × 10⁶ mole of H₂ is produced by

= 2 × 1.7176 × 10⁶ moles of  electron

= 3.435 ×10⁶ moles of electron

We know that

charge = moles of electron × F

          =  (3.435 ×10⁶ × 96500) C

           =  3.31 × 10¹¹ C

(c) We know that,

Voltage = \frac{energy}{charge}  =  \frac{J}{C}

1.44 V = \frac{energy}{3.31 . 10^{11} }

Energy = 1.44 V × 3.31 × 10¹¹ C

            =  4.766 × 10¹¹ Joules

Thus from the above conclusion we can say that, coulombs are supplied at 1.44 V, then 4.766 × 10¹¹ joules are produced.

Learn more about Fuel Cell here : brainly.com/question/16612142

#SPJ4

Disclaimer : The question given was incomplete on portal, Here is the complete question.

Question : Car manufacturers are developing engines that use H₂ as fuel. In Iceland, Sweden, and other parts of Scandinavia countries, where hydroelectric plants produce inexpensive electric power, the H₂ can be made industrially by the electrolysis of water.

a) How many moles of electrons flow per mole of reaction ?

b) How many coulombs are needed to produce 3.53X10⁶ L of H₂ gas at   12.0 atm and 25°C.

c) If the coulombs are supplied at 1.44 V, how many joules are produced?

8 0
2 years ago
Electronegativity is a measure of an atom’s affinity for electrons. Which of the following statements is true? Electronegativity
jekas [21]

Answer: Electronegativity increases as the size of an atom decrease.

Explanation: Electronegativity is the measure of the ability of an atom in a bond to attract electrons to itself.

Electronegativity increases across a period and decreases down a group.

Towards the left of the table, valence shells are less than half full, so these atoms (metals) tend

to lose electrons and have low electronegativity. Towards the right of the table, valence shells are more than half full, so these atoms (nonmetals) tend to gain electrons and have high electronegativity.

Down a group, the number of energy levels (n) increases, and so does the distance between the nucleus and the outermost orbital. The increased distance and the increased shielding weaken the nuclear attraction, and so an atom can’t attract electrons as strongly.

4 0
3 years ago
Give all possible ml values for orbitals that have each of the following: (a) l = 2; (b) n = 1; (c) n = 4, l = 3.
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Answer:

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Explanation:

The rules for electron quantum numbers are:

1. Shell number, 1 ≤ n

2. Subshell number, 0 ≤ l ≤ n − 1

3. Orbital energy shift, -l ≤ ml ≤ l

4. Spin, either -1/2 or +1/2

So in our exercise,

(a) l = 2; equivalent with with sublevel <em>d</em>

-l ≤ ml ≤ l, ml = 0, ±1, ±2, equivalent with dxy, dxz, dyz, dx2-y2, dz2

(b) n = 1;

n = 1, only 01 level

l = 0, equivalent with sublevel <em>s</em>

ml = 0

(c) n = 4, l = 3.

l = 3, equivalent with sublevel <em>f</em>

ml = 0, ±1, ±2, ±3, ±4

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<span>he specific heat capacity of liquid water is 4.186 J/gm K.</span>
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