Answer:
Explanation:
Given that:
distance (z) = 7.86 m
mass of the person = 81.7 kg
Acceleration (a) = 0.729 m/s²
By using Newton's second law along the vertical axis:
T = 81.7 (0.729 +9.8)
T = 860.22 N
The work done now is:
<span>c. contains different kind of matter</span>
The displacement would be the final position (37) minus the initial position (50) if using the displacement formula.
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Below is the solution:
9.43 m/s
<span>F = -kx </span>
<span>k = 400 N/m </span>
<span>PE= 0.5kx^2 = 0.5mv^2 </span>
<span>solve, v=9.43 m/s</span>
