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tia_tia [17]
2 years ago
10

Which of the following is true about a hypothesis?

Physics
1 answer:
Leviafan [203]2 years ago
7 0

Answer:

i think you need to show a picture

Explanation:

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A 2-kg ball is thrown at 3 m/s. What is the ball's momentum? *
crimeas [40]

Answer:

Given

mass (m) =2kg

velocity (v) =3m/s

momentum (p) =?

Form

p=mv

2kgx3m/s

p=6kg.m/s

the momentum of ball's =6kg.m/s

8 0
3 years ago
A scientist pours 0.120 L of solution A into an Erlenmeyer flask. She adds 2.345 L of solution B. How many significant figures a
nika2105 [10]
0.120L + 2.345L = 2.465L = 4 significant figures in the answer
6 0
3 years ago
An eagle flying at 15 m/s has 600 J of kinetic energy. About how much is the eagles mass?
Eduardwww [97]

Answer:

5.33kg

Explanation:

Given parameters:

Velocity of eagle  = 15m/s

Kinetic energy of the eagle = 600J

Unknown:

Mass of the eagle  = ?

Solution:

The kinetic energy of any body is the energy due to the motion of a body. There are different forms of kinetic energy some of which are thermal, mechanical, electrical  energy.

The formula of kinetic energy is given as;

              Kinetic energy  = \frac{1}{2} m v²

where m is the mass, V is the velocity

   substitute the parameters in the equation;

                       600  = \frac{1}{2} x m x 15²

                     225m  = 1200

                            m  = \frac{1200}{225}    = 5.33kg

3 0
2 years ago
Volcanoes that have fast flowing liquid lava will be narrow like a river
vodomira [7]

Answer:

Shield volcanoes, the third type of volcano, are built almost entirely of fluid lava flows. Flow after flow pours out in all directions from a central summit vent, or group of vents, building a broad, gently sloping cone of flat, domical shape, with a profile much like that of a warrior's shield.

Explanation:

8 0
2 years ago
Earth is about 150 million kilometers from the Sun, and the apparent brightness of the Sun in our sky is about 1300 watts/m2. Us
nalin [4]

Answer:

13 W/m^2

Explanation:

The apparent brightness follows an inverse square law, therefore we can write:

I \propto \frac{1}{r^2}

where I is the apparent brightness and r is the distance from the Sun.

We can also rewrite the law as

\frac{I_2}{I_1}=\frac{r_1^2}{r_2^2} (1)

where in this problem, we have:

I_1 = 1300 W/m^2 apparent brightness at a distance r_1, where

r_1 = 150 million km

We want to estimate the apparent brightness at r_2, where r_2 is ten times r_1, so

r_2 = 10 r_1

Re-arranging eq.(1), we find I_2:

I_2 = \frac{r_1^2}{r_2^2}I_1 = \frac{r_1^2}{(10r_1)^2}(1300)=\frac{1}{100}(1300)=13 W/m^2

5 0
3 years ago
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