Time = (distance) / (speed)
Time = (65 meters) / (0.23 m /s)
Time = (65 / 0.23) sec
<em>Time = 282.6 seconds </em>( that's 4 minutes 42.6 seconds)
The light gets reflected by the mirror
The amplitude of the wave is determined as 0.0215 m.
<h3>What is amplitude of a wave?</h3>
The amplitude of a wave is the maximum displacement of the wave.
The amplitude of the wave is calculated as follows;
<h3>Amplitude of the wave</h3>
A cos(Φ) = 0.02 ---- (1)
-80π A sin(Φ) = - 2
A sin(Φ) = 1/40π ----- (2)
Divide (2) by (1)
tan(Φ) = 1/(0.02 x 40π)
tan(Φ) = 1/(0.8π)
Ф = tan⁻¹( 1/(0.8π))
Ф = 0.3787
A cos (0.3787) = 0.02
A (0.929) = 0.02
A = 0.0215 m
Thus, the amplitude of the wave is determined as 0.0215 m
Learn more about amplitude of wave here: brainly.com/question/19036728
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Answer:
the only affect that the teacher does is tell or show what the learner needs to do they will attempt to do it
Explanation:
the learner will be able to get a specific thing done if show how to do it the learner will do a better job if just told to do it they will do it but not perfect or good kind of blind folding someone and telling the to open a padlock without light.
Answer:
Net force = 0.0191 N
T=0.00054 N.m
p=99.2 μC.cm
Explanation:
Given that
L= 6.2 cm
q₁= 16μC
q₂=1μC
E= 1174 N/C
We know that
F = q E
F₁ = q₁ E
F₁ = 0.018 N
F₂=q₂ E
F₂=0.0011 N
Net force = F₁+F₂
Net force = 0.0191 N
Torque ,T
T = (F₁-F₂) L/2
T = (0.018 - 0.0011 ) x 0.032
T=0.00054 N.m
Polarization ,p
p= q d
p= 16 x 6.2 μC.cm
p=99.2 μC.cm