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3 years ago

A meteor is approaching Earth. Which statement about its motion is true?

Physics

2 answers:

Aleksandr-060686 [28]3 years ago

6 0

<h2>Answer:</h2>

｡･:*:･ﾟ★,｡･:*:･ﾟ☆여보세요｡･:*:･ﾟ★,｡･:*:･ﾟ☆　

꘎♡━━━━━━━━━━━━━━━♡꘎

⋆ ˚｡⋆୨୧˚ The answer is below ˚୨୧⋆｡˚ ⋆

꘎♡━━━━━━━━━━━━━━━♡꘎

B) The meteor accelerates. It accelerates due to Earths gravitational pull on the meteor.

☆♬○♩●♪Have a nice day♩✧♪●♩○♬☆

Maslowich3 years ago

3 0

B. The meteor accelerates

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A top fuel dragster covers the quarter mile in 4.5 seconds. What is it's speed in miles per hour

gladu [14]

<span>Distance in Miles (.25) x 3600 (seconds in an hour) / time in seconds = 200 MPH. Drag racing calculates the top speed via a speed trap starting 66 feet from the finish line.</span>

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3 years ago

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A dog has a mass of 60kg and an acceleration of 2m/s/s. What is the force of the dog?

attashe74 [19]

Answer:

120 N

Explanation:

F=ma therefore 60kg times 2m/s^2 is 120 N

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3 years ago

John’s mass is 95.6 kg, and Barbara’s is 55.3 kg. He is standing on the x axis at xJ = +10.9 m, while she is standing on the x a

Anna11 [10]

Answer:Shifted towards Left by distance of 2.243 m

Explanation:

Given

Mass of john $m_1=95.6 kg$

Mass of barbara $m_2=55.3 kg$

John is standing at $x=10.9 m$

Barbara is standing at $x=2.50 m$

$x_{com}=\frac{m_1x_1+m_2x_2}{m_1+m_2}$

$x_{com}=\frac{95.6\times 10.9+55.3\times 2.5}{95.6+55.3}$

$x_{com}=\frac{1180.29}{150.9}$

$x_{com}=7.821 m$

Now if they change their Position then

$x'_{com}=\frac{95.6\times 2.5+55.3\times 10.9}{95.6+55.3}$

$x'_{com}=\frac{841.77}{150.9}$

$x'_{com}=5.578$

Thus we can see that center of mass shifted towards left by a distance of $2.243 m$ because heavier is shifted towards left

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3 years ago

A certain spring stores 10.0J of potential energy when it isstretched by 2.00cm from its equilibrium position.How much potential

qaws [65]

Answer:

Answered

Explanation:

x= 0.02 m

E_p= 10.0 J

E_p= 0.5kx^2

10= 0.5k(0.02)^2

solving we get

K= 50.0 N/m

Now

E'_p= 0.5kx'^2

E'_p= 0.5×50×(0.04)^2

E'_p=40 J

b) potential energy is a scalar quantity and it only depends magnitude and not direction so it will remain same in compression and expansion both

c) 20 J = 0.5×50,000×x^2

solving

x= 0.028 m

d) k is 50.0 N/m from above calculation

3 0

3 years ago

A parallel-plate capacitor is connected to a battery. What happens to the stored energy if the plate separation is doubled while

marta [7]

Answer:

Explanation:

Energy stored in a parallel plate capacitor is given by:

$U=\frac{1}{2}CV^2\\\\C=\frac{A\epsilon_{o}}{d}\\\\then\\\\U=\frac{1}{2}\frac{A\epsilon_{o}}{d}V^2--(1)\\\\$

As capacitor remains connected to the battery so V remains constant. As can be seen from (1) that energy is inversely proportional to the separation between the plates so as 'd' becomes doubled, energy decreases by the factor of 2.

3 0

3 years ago

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