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3 years ago

What is current tallest proposed building project right now?

2 answers:

4 0

At this point of time, there have been many planned and proposed building projects for the future, but there is one that really stands out more than the rest of them. The current tallest proposed building project right now in the world is the X-Seed 4000. It will reach approximately a whopping 4000 meters, or about 13,123 feet. This is approximately 2.5 miles, or 4 kilometers. The only problem is how we are going to build it. It most likely will not be built any time soon, partially because the cost of building it will be nearly one trillion dollars in US money. That is a lot of money! Additionally, this monster skyscraper can accompany around one million inhabitants or even more, significantly proving its insane size and spatial capacity. Anyways, this building is the current tallest proposed building project right now in the world. Hope this helped answer your question for you. Good day to you.

fenix001 [56]3 years ago

3 0

Explanation:

Jeddah

Is the tallest building proposed ‍♀️building project right now

Hope it helps♥️

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When buttons or switches are pressed by humans for arbitrary periods of time, we need to convert a signal level to a pulse. In t

ddd [48]

Answer:

The FSM uses the states along with the generation at the P output on each of the positive edges of the CLK. The memory stores the previous state in the machine and the decoder generates a P output based on the previous state.

Explanation:

The code is in the image.

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3 years ago

Please help me bro come on

melomori [17]

Answer:

12

Explanation:

5 • 3 = 15
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3 years ago

Read 2 more answers

A smooth sphere with a diameter of 6 inches and a density of 493 lbm/ft^3 falls at terminal speed through sea water (S.G.=1.0027

Pachacha [2.7K]

Given:

diameter of sphere, d = 6 inches

radius of sphere, r = $\frac{d}{2}$ = 3 inches

density, $\rho}$ = 493 lbm/ $ft^{3}$

S.G = 1.0027

g = 9.8 m/ $m^{2}$ = 386.22 inch/ $s^{2}$

Solution:

Using the formula for terminal velocity,

$v_{T}$ = $\sqrt{\frac{2V\rho g}{A \rho C_{d}}}$ (1)

$(Since, m = V\times \rho)$

where,

V = volume of sphere

$C_{d}$ = drag coefficient

Now,

Surface area of sphere, A = $4\pi r^{2}$

Volume of sphere, V = $\frac{4}{3} \pi r^{3}$

Using the above formulae in eqn (1):

$v_{T}$ = $\sqrt{\frac{2\times \frac{4}{3} \pir^{3}\rho g}{4\pi r^{2} \rho C_{d}}}$

$v_{T}$ = $\sqrt{\frac{2gr}{3C_{d}}}$

$v_{T}$ = $\sqrt{\frac{2\times 386.22\times 3}{3C_{d}}}$

Therefore, terminal velcity is given by:

$v_{T}$ = $\frac{27.79}{\sqrt{C_d}}$ inch/sec

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4 years ago

A waste stabilization pond is used to treat a dilute municipal wastewater before the liquid is discharged into a river. The infl

german

Answer:

BOD concentration at the outflow = 17.83 mg/L

Explanation:

given data

flow rate of Q = 4,000 m³/day

BOD1 concentration of Cin = 25 mg/L

volume of the pond = 20,000 m³

first-order rate constant equal = 0.25/day

to find out

What is the BOD concentration at the outflow of the pond

solution

first we find the detention time that is

detention time t = $\frac{volume}{flow rate}$

detention time t = $\frac{20000}{4000}$

detention time = 5 days

BOD concentration at the outflow of pond is express as

BOD concentration at the outflow = $Cin ( 1 - e^{-kt} )$

here k is first-order rate constant and t is detention time and Cin is BOD1 concentration

BOD concentration at the outflow = $25 ( 1 - e^{-0.25(5)} )$

BOD concentration at the outflow = 17.83 mg/L

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4 years ago

Truth table for (A+B)(B+C)

serg [7]

Answer:

A truth table is a logical expression of the given inputs specially in boolean algebra and boolean functions in computer science and digital electronics.

Explanation:

Number of variables are 3 i.e A,B and C

so the number of bits are 2^3=8

A B C A+B B+C (A+B)(B+C)

0 0 0 0 0 0

0 0 1 0 1 0

0 1 0 1 1 1

0 1 1 1 1 1

1 0 0 1 0 0

1 0 1 1 1 1

1 1 0 1 1 1

1 1 1 1 1 1

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4 years ago