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Feliz [49]
3 years ago
5

30 points for all 5 answers please

Physics
1 answer:
Lynna [10]3 years ago
8 0

Answer:

he is doing science

he is doing science

he is doing science

he is doing science

he is doing science

Explanation:

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A person observes a firework display for A safe distance of .750 km. Assuming that sound travels at 340 m/s in air what is the t
WINSTONCH [101]

Answer:

t = 2.2 s

Explanation:

Given that,

A person observes a firework display for A safe distance of 0.750 km.

d = 750 m

The speed of sound in air, v = 340 m/s

We need to find the between the person see and hear a firework explosion. let it is t. So, using the formula of speed.

v=\dfrac{d}{t}\\\\t=\dfrac{d}{v}\\\\t=\dfrac{750\ m}{340\ m/s}\\\\t=2.2\ s

So, the required time is 2.2 seconds.

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Which one of the following is not a fundamental physical quantity??! A. Temperature b. Current c. Area d. Mass​
Hatshy [7]

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Out of this, Area is not a fundamental physical quantity.

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Is visible light a form of<br> radiation? Explain.
natali 33 [55]

Answer:

Yes,in fact visible 'light' is a form of radiation, which can be defined as an energy that travels in the form of electromagnetic waves. It can also be described as a flow of particle-like 'wave-packets', called photons, that travel constantly at the speed of light (about 300 000 kilometres per second).

Explanation:

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