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Feliz [49]
3 years ago
5

30 points for all 5 answers please

Physics
1 answer:
Lynna [10]3 years ago
8 0

Answer:

he is doing science

he is doing science

he is doing science

he is doing science

he is doing science

Explanation:

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On the Moon, the acceleration due to the effect of gravity is only about 1/6 of that on Earth. An astronaut whose weight on Eart
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A = 94.22 Newtons

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Gravity on the moon is 1.62 m/s^2
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A low C (f = 65Hz) is sounded on a piano. If the length of the piano wire is 2.0 m and its mass density is 5.0 g/m2, determine t
LuckyWell [14K]

Answer:

Tension of the wire(T) = 169 N

Explanation:

Given:

f = 65Hz

Length of the piano wire (L) = 2 m

Mass density = 5.0 g/m² = 0.005 kg/m²

Find:

Tension of the wire(T)

Computation:

f = v / λ

65 = v / 2L

65 = v /(2)(2)

v = 260 m/s

T = v² (m/l)

T = (260)²(0.005/2)

T = 169 N

Tension of the wire(T) = 169 N

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3 years ago
Under which conditions do both convex and concave mirrors form virtual images? State whether or not each can form a real image.I
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At a certain location the horizontal component of the earth's magnetic field is
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6 0
3 years ago
The standard emf for the cell using the overall cell reaction below is +2.20 V: 2Al(s) + 3I2 (s) → 2Al3+ (aq) + 6I− (aq) The emf
Triss [41]

Answer: +2.10V

Explanation:

2Al(s)+3I_2(s)\rightarrow 2Al^{3+}(aq)+6I^-(aq)

Using Nernst equation :

E_{cell}=E^o_{cell}-\frac{0.059}{n}\log K

E_{cell}=E^o_{cell}-\frac{0.059}{n}\log [Al^{3+}]^2\times [I^-]^6

where,

E^o_{cell} = standard emf for the cell = +2.20 V

n = number of electrons in oxidation-reduction reaction = 6

E_{cell} = emf of the cell = ?

[Al^{3+}]  = concentration = 5.0\times 10^{-3}M

[I}^{-}]  = concentration = 0.10M

Now put all the given values in the above equation, we get:

E_{cell}=+2.20-\frac{0.059}{6}\log [5.0\times 10^{-3}]^2\times [0.10]^6

E_{cell}=2.10V

The standard emf for the cell using the overall cell reaction below is +2.10 V

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