C) A laser beam looks bent when it passes through glass blocks.
Hope this helps!
The volume of the textbook calculated by the student written to 3 significant figures is 992cm³
- According to this question, a student calculates the volume of his textbook and arrived at an answer of 991.880 cm³.
- To round up this digit to 3 significant figures, which means that only 3 significant numbers should appear in the answer.
- To do this, the number after the third number is 8, which means we can round up the value of 1 to 2. Hence, the volume of the textbook calculated by the student is 992cm³ in 3 s.f.
Learn more at: brainly.com/question/16563962?referrer=searchResults
Answer:
increase
Explanation:
At the skate park when a skateboarder wants to skate down a ramp, the skate boarder wishes to move faster and with speed so that it help him to skate more time. This can only be achieved if the all the forces acting on him will increase as he skates down the ramp without much of the frictional force acting on the wheels of the skate board. The less friction force acts on the wheel, the more he can skate with more speed.
Thus, the skateboarder wants the force to be increase that is acting on him.
Answer:
The mass percent of copper as element is the same.
Explanation:
First of all we need the reaction that is presented below:
→ ![CuO_{(s)} + CO_{2 (g)}](https://tex.z-dn.net/?f=CuO_%7B%28s%29%7D%20%2B%20CO_%7B2%20%28g%29%7D)
The mass percent of copper (Cu) as element is the same because of during the reaction the element only transform its nature from copper carbonate (
) to copper oxide (
), the latter is a solid and will remain in the system.
On the other hand, you will note that the global percentage mass will be small because of the reaction produce (
) that is a gas and this one will escape for the system.
Have a great day!
<h3>Answer:</h3>
64 g O₂
<h3>General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
<u>Stoichiometry</u>
- Using Dimensional Analysis
<h3>Explanation:</h3>
<u>Step 1: Define</u>
[RxN - Balanced] CH₄ + 2O₂ → CO₂ + 2H₂O
[Given] 36 g H₂O
[Solve] x g O₂
<u>Step 2: Identify Conversions</u>
[RxN] 2 mol O₂ → 2 mol H₂O
[PT] Molar Mass of O - 16.00 g/mol
[PT] Molar Mas of H - 1.01 g/mol
Molar Mass of O₂ - 2(16.00) = 32.00 g/mol
Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol
<u>Step 3: Stoichiometry</u>
- Set up conversion:
![\displaystyle 36 \ g \ H_2O(\frac{1 \ mol \ H_2O}{18.02 \ g \ H_2O})(\frac{2 \ mol \ O_2}{2 \ mol \ H_2O})(\frac{32.00 \ g \ O_2}{1 \ mol \ O_2})](https://tex.z-dn.net/?f=%5Cdisplaystyle%2036%20%5C%20g%20%5C%20H_2O%28%5Cfrac%7B1%20%5C%20mol%20%5C%20H_2O%7D%7B18.02%20%5C%20g%20%5C%20H_2O%7D%29%28%5Cfrac%7B2%20%5C%20mol%20%5C%20O_2%7D%7B2%20%5C%20mol%20%5C%20%20H_2O%7D%29%28%5Cfrac%7B32.00%20%5C%20g%20%5C%20O_2%7D%7B1%20%5C%20mol%20%5C%20O_2%7D%29)
- Divide/Multiply [Cancel Units]:
![\displaystyle 63.929 \ g \ O_2](https://tex.z-dn.net/?f=%5Cdisplaystyle%2063.929%20%5C%20g%20%5C%20O_2)
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 2 sig figs.</em>
63.929 g O₂ ≈ 64 g O₂