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kvv77 [185]
3 years ago
6

WILL MARK BRANLIEST FOR CORRECT ANSWER! Given the following equation, write the expression for its relative rate.

Chemistry
1 answer:
USPshnik [31]3 years ago
7 0

\tt -\dfrac{1}{2}\dfrac{d[N_2O]}{dt}=\dfrac{1}{2}\dfrac{d[N_2]}{dt}=\dfrac{1}{1}\dfrac{d[O_2]}{dt}

<h3>Further explanation</h3>

Reaction

2N2O(g) — 2N2(g) + O2(g)

Required

relative rate

Solution

The reaction rate (v) shows the change in the concentration of the substance (changes in addition to concentrations for reaction products or changes in concentration reduction for reactants) per unit time.

so the relative rates for the reaction above are :

\tt -\dfrac{1}{2}\dfrac{d[N_2O]}{dt}=\dfrac{1}{2}\dfrac{d[N_2]}{dt}=\dfrac{1}{1}\dfrac{d[O_2]}{dt}

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Answer:

Clavulanic acid has two (2) chiral centers.

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A chiral center is a center (usually carbon) with four different substituents.

The structure of clavulanic acid is shown in the attachment below.

Consider the labeled diagram in the attachment,

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