Let's translate the verbal language to algebraic language.
She rides to and from school 5 days per week, 6.25 miles each route => 5*2*6.25 miles = 62.5 miles.
She rides additioanly around the park 2.5 miles for each trip t => 2.5*t = 2.5t
Total miles of her rides per week: 62.5 miles + 2.5t
She wants to ride minimum 85 miles => 62.5 + 2.5t ≥ 85
Then, the situation is represented by this inequality:
2.5t + 62.5 ≥ 85
You can develop it and get to several equivalent inequalities, for example:
2.5t ≥ 85 - 62.5
2.5t ≥ 22.5
t ≥ 9
Any of the four forms are equivalent and a valid answer.
Answer:
Jay started with $148.5 and Kay with $24.75.
Step-by-step explanation:
With the information provided you know that Jay had 6 times as much money as Kay wich can be expressed as:
J=6K, where
J is the money Jay had
K is the money Kay had
Also, you know that Jay gave Kay $33 and Jay now has twice as much money as Kay, which would be:
J-33=2(K+33)
Now, you can replace J=6K in this equation and solve for K:
6K-33=2K+66
6K-2K=66+33
4K=66
K=24.75
Then, you can replace the value of K in J=6K:
J=6*24.75
J=148.5
According to this, the answer is that Jay started with $148.5 and Kay with $24.75.
ummmm it could be third one i guesss
Answer:
The answer is 9x² - 6x - 1
Step-by-step explanation:
∵ (6x³ + x² - 10x - 1) - (6x³ - 8x² - 4x) =
0 + 9x² - 6x - 1 = 9x² - 6x - 1
