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Bezzdna [24]
3 years ago
8

There are two piston-cylinder systems that each contain 1 kg of an idea gas at a pressure of 300 kPa and temperature of 350 K. T

he two systems then undergo two different processes:
System 1 undergoes process 1 as follows:
Isobaric heating to 500 K, then compressed to a pressure of 500 kPa and a temperature of 600 K.

System 2 undergoes process 2 as follows:
Directly compressed in one step to a pressure 500 kPa and a temperature of 600 K

We "measure" the entropy of each system before and after the process. Which system had the biggest entropy change?

a. System 1
b. System 2
c. Entropy change is the same for both systems
Engineering
1 answer:
Nataly_w [17]3 years ago
8 0

Answer:

Entropy change is same for both systems because entropy is a state function i.e., it doesn't depend on the path by which the system arrived at it's present state (500 kPa, 600 K) from initial state (300 kPa, 350 K) .

Explanation:

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Answer:

#include<stdio.h>

#include<stdlib.h>

#include<unistd.h>

#include<sys/types.h>

#include<string.h>

#include<pthread.h>

//#include<sys/wait.h>

int main(int argc, char** argv)

{

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int fd2[2];

int fd3[2];

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pid_t p,q;

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}

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{

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 return 1;

}

if (pipe(fd3)==-1)

{

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}

if (pipe(fd4)==-1)

{

 fprintf(stderr, "Pipe Failed" );

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}

p = fork();

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 int k = strlen(concat_str);

 int i;

 for (i=0; i<strlen(fixed_str); i++)

 {

  concat_str[k++] = fixed_str[i];

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 close(fd1[1]);

 wait(NULL);

//.......................................................................

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}

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