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DiKsa [7]
3 years ago
7

Rank the metals from most reactive (1) to least reactive (3).

Chemistry
2 answers:
Citrus2011 [14]3 years ago
8 0

Answer:

1:Silver

2:Strontium

3:Technetium

Hope this helps!! Good Luck!!

alisha [4.7K]3 years ago
6 0

Answer:

Silver: 3

Strontium: 1

Technetium: 2

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If i have 340mL of a 1.5 M NaBr solution, What will the concentration be for 1000mL?
Gekata [30.6K]

Answer:

0.51M

Explanation:

Given parameters:

Initial volume of NaBr = 340mL

Initial molarity  = 1.5M

Final volume  = 1000mL

Unknown:

Final molarity = ?

Solution;

This is a dilution problem whereas the concentration of a compound changes from one to another.

In this kind of problem, we must establish that the number of moles still remains the same.

    number of moles initially before diluting = number of moles after dilution

Number of moles  = Molarity x volume

Let us find the number of moles;

          Number of moles  = initial volume x initial molarity

Convert mL to dm³;

                  1000mL  = 1dm³

                     340mL gives \frac{340}{1000}   = 0.34dm³

Number of moles  = initial volume x initial molarity  = 0.34 x 1.5 = 0.51moles

Now to find the new molarity/concentration;

               Final molarity  = \frac{number of moles}{Volume}    = \frac{0.51}{1}    = 0.51M

We can see a massive drop in molarity this is due to dilution of the initial concentration.

6 0
3 years ago
Three forms of radiation are also called ionizing radiation
Trava [24]

Answer:

Alpha Particle, Beta Particles and Gamma Rays

Explanation:

8 0
2 years ago
How many moles are in 1.2×10^3g of ammonia
Diano4ka-milaya [45]

Answer:8

Explanation:

4 0
3 years ago
Read 2 more answers
Please help with this question!
Alex17521 [72]

Answer:

A) potential energy is stored energy. Kenetic energy is energy of motion.

6 0
2 years ago
What is the kinetic energy of the emitted electrons when cesium is exposed to UV rays of frequency 1.0×1015Hz?
Anvisha [2.4K]
In order to emit electrons, the cesium will have to absorb photons. Each photon will knock out one electron by transferring its energy to the electron. Therefore, by the principle of energy conservation, the energy of the removed electron will be equal to the energy of the incident photon. That energy is calculated using Planck's equation:

E = hf

E = 6.63 x 10⁻³⁴ * 1 x 10¹⁵
E =  6.63 x 10⁻¹⁹ Joules

The electron will have 6.63 x 10⁻¹⁹ Joules of kinetic energy
3 0
3 years ago
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