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olasank [31]
3 years ago
13

Please help me with this chemistry question, ill mark as brainliest

Chemistry
1 answer:
Anna35 [415]3 years ago
7 0
All of the acid molecules in beaker 1 dissociate fully and exist as and ions. As a result, beaker 1 represents a strong acid solution. The majority of the molecules in beaker 2 are undissociated.
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What is the mass, in grams, of 2.50 * 10-3 mol of aluminum sulfate?
Nonamiya [84]

Answer:

The mass is 0.855 grams (option A)

Explanation:

Step 1: Data given

aluminium sulfate = Al2(SO4)3

Numer of moles Al2(SO4)3 = 2.50 * 10^-3 moles

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Step 3: Calculate mass Al2(SO4)3

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Mass Al2(SO4)3 = 2.5 *10^-3 moles * 342.175 g/mol

Mass Al2(SO4)3 = 0.855 grams

The mass is 0.855 grams (option A)

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