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Answer:
The maximum height reached by the rocket is 486.53 m
Explanation:
Given;
initial velocity of the rocket, u = 0
acceleration of the rocket, a= 20 m/s²
duration of the rocket first motion, t = 4 s
The distance traveled by the rocket before its thrust failed
h₁ = ut + ¹/₂at²
h₁ = 0 + ¹/₂ x 20 x 4²
h₁ = 160 m
The second distance moved by the rocket is calculated as follows;
The velocity of the rocket before its thrust failed;
v = u + at
v = 0 + 20 x 4
v = 80 m/s
This becomes the initial velocity for the second stage
At maximum height, the final velocity = 0

The maximum height reached by the rocket = h₁ + h₂
= 160 + 326.53
= 486.53 m
Answer:
Final velocity v = 4 m/s
Explanation:
Given:
Initial velocity u = 0 m/s
Acceleration a = 0.16 m/s²
Distance s = 50 m
Find:
Final velocity v
Computation:
Using; v² = u² + 2as
v² = (0)² + 2(0.16)(50)
v² = 16 m/s
v = 4 m/s
Final velocity v = 4 m/s
Answer:
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