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Nezavi [6.7K]
3 years ago
15

What is the kinetic energy of a 0.5 kg soccer ball that is traveling at a

Physics
1 answer:
Charra [1.4K]3 years ago
3 0

Answer:

kinetic energy = 1/2mv²

k.E =1/2 X 0.5 X 3²

k.e = 9/4

K.E = 2.25j

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2 years ago
A rocket at fired straight up from rest with a net upward acceleration of 20 m/s2 starting from the ground. After 4.0 s, the thr
8_murik_8 [283]

Answer:

The maximum height reached by the rocket is 486.53 m

Explanation:

Given;

initial velocity of the rocket, u = 0

acceleration of the rocket, a= 20 m/s²

duration of the rocket first motion, t = 4 s

The distance traveled by the rocket before its thrust failed

h₁ = ut + ¹/₂at²

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The second distance moved by the rocket is calculated as follows;

The velocity of the rocket before its thrust failed;

v = u + at

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At maximum height, the final velocity = 0

v_f^0 = v_i^2 - 2gh_2\\\\0 = (80)^2 - (2 \times 9.8)h_2\\\\0 = 6400 - 19.6h_2\\\\19.6h_2 = 6400\\\\h_2 = \frac{6400}{19.6} \\\\h_2 = 326.53 \ m

The maximum height reached by the rocket = h₁ + h₂

                                                                          = 160 + 326.53

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2 years ago
a sprinter starts from rest and accelerates at a rate of 0.16 ms ^-2 over a distance of 50.0 meters . How fast is the athlete tr
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Answer:

Final velocity v = 4 m/s

Explanation:

Given:

Initial velocity u = 0 m/s

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Final velocity v

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Using; v² = u² + 2as

v² = (0)² + 2(0.16)(50)

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Final velocity v = 4 m/s

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