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SCORPION-xisa [38]
3 years ago
5

What is the solution to the problem expressed to the correct number of significant figures? 12.0/7.11=?

Chemistry
1 answer:
xxMikexx [17]3 years ago
3 0

Answer:

1.69.

Explanation:

  • The solution = 12.0 / 7.11 = 1.687 = 1.69.
  • The rule of significant figures for division states that: the results are reported to the fewest significant  figures.
  • 12.0 contains 3 significant figures.
  • 7.11 contains 3 significant figures.

So, the solution should contain 3 significant figures.

  • Now, the issue id of rounding; In a series of calculations, carry the extra digits through to  the final result, then round.
  • If the digit to be removed is equal to or greater than 5, the preceding digit is  increased by 1.
  • The digit that should be removed is 7 that is larger than 5 so increase the preceding digit by 1.
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Please help! 35 points for a valid answer!
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Answer:

Oxidation  half  reaction  is  written   as    follows when  using  using  reduction potential  chart

example  when  using  copper  it is  written  as  follows

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After a covalent bond has stabilized an atom, the atom will have
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Given the following equation: 2K + Cl2 -&gt; 2KCl How many grams of KCl is produced from 4.00 g of K and excess Cl2?
Thepotemich [5.8K]

Answer:

42.65g

Explanation:

Given parameters:

Mass of K = 4g

Unknown: Mass of KCl

Solution:

  Complete equation of the reaction:

              2K + Cl₂ → 2KCl

To solve this problem, we know that the reactant in short supply is potassium K and this dictates the amount of products that would be formed. The chlorine gas is in excess and we can't use it to determine the amount of product that would form.

Now, we work from the known to the unknown. Since we know the mass of K given in the reaction, we can simply find the molar relationship between the reacting potassium and the product. We simply convert the mass to mole and compare to the product. From there we can find the mass of KCl that would be produced.

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 Therefore 0.103mol of K will produce 0.103mol of KCl

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X = Ar

Atomic Number of Argon, Z = 18

Mass Number, A = 18 + 22 = 40

40.18.Ar

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