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SCORPION-xisa [38]
3 years ago
5

What is the solution to the problem expressed to the correct number of significant figures? 12.0/7.11=?

Chemistry
1 answer:
xxMikexx [17]3 years ago
3 0

Answer:

1.69.

Explanation:

  • The solution = 12.0 / 7.11 = 1.687 = 1.69.
  • The rule of significant figures for division states that: the results are reported to the fewest significant  figures.
  • 12.0 contains 3 significant figures.
  • 7.11 contains 3 significant figures.

So, the solution should contain 3 significant figures.

  • Now, the issue id of rounding; In a series of calculations, carry the extra digits through to  the final result, then round.
  • If the digit to be removed is equal to or greater than 5, the preceding digit is  increased by 1.
  • The digit that should be removed is 7 that is larger than 5 so increase the preceding digit by 1.
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Is this a real question? It’s B
6 0
3 years ago
Calculate the hydronium ion concentration in an aqueous solution with a poh of 4.33 at 25°c.
Jlenok [28]

Taking into account the definition of pH and pOH, the hydronium ion concentration in an aqueous solution with a pOH of 4.33 at 25°c is 2.138×10⁻¹⁰ M.

<h3>Definition of pH</h3>

pH is a measure of acidity or alkalinity that indicates the amount of hydrogen ions present in a solution or substance.

The pH is defined as the negative base 10 logarithm of the activity of hydrogen ions, that is, the concentration of hydrogen ions or  hydronium ion H₃O⁺:

pH= - log [H⁺]= - log [H₃O⁺]

<h3>Definition of pOH</h3>

Similarly, pOH is a measure of hydroxyl ions in a solution and is expressed as the logarithm of the concentration of OH⁻ ions, with the sign changed:

pOH= - log [OH⁻]

<h3>Relationship between pH and pOH</h3>

The following relationship can be established between pH and pOH:

pOH + pH= 14

<h3>Concentration of hydronium ions</h3>

Being pOH= 4.33, pH is calculated as:

pH + 4.33= 14

pH= 14 - 4.33

<u><em>pH= 9.67</em></u>

Replacing in the definition of pH the concentration of hydronium ions is obtained:

- log [H₃O⁺]= 9.67

Solving:

[H₃O⁺]= 10⁻⁹ ⁶⁷

<u><em>[H₃O⁺]= 2.138×10⁻¹⁰ M</em></u>

Finally, the hydronium ion concentration in an aqueous solution with a pOH of 4.33 at 25°c is 2.138×10⁻¹⁰ M.

Learn more about pH and pOH:

brainly.com/question/16032912

brainly.com/question/13557815

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4 0
2 years ago
Determine the mass of oxygen in a 7.2- g sample of A l 2 (S O 4 ) 3 .
astraxan [27]
Molar mass of A l 2 (S O 4 ) 3 = 342.15 g/mol
7.2g/ 342.15 g/mol
you can get number of moles.
then multiply that by12
7 0
3 years ago
What is the electronic configuration for K2Cr2O7
dybincka [34]

Answer:

Potassium compounds are quite common and are extremely useful for a variety of purposes. Potash and other potassium compounds have been used for centuries in the manufacture of glass products. Today 95% of the potassium compounds gathered in the world is used in the manufacture of fertilizers.

Potassium dichromate is an inorganic chemical compound possess immense industrial and laboratory importance. It is an orange crystalline solid with the chemical formula K2Cr2O7. It is a strong oxidizing agent and is soluble in water. It is used in the volumetric estimation of ferrous salts, iodides and sulphides for the preparation of chrome alum, chrome yellow and chrome red.

8 0
2 years ago
At constant pressure and 25^0C , a sample of gas occupies 4.5lit. at what temperature will the gas occupy 9.0lit.​
olga55 [171]

Answer:

Final temperature = 149 K

Explanation:

Given data:

Initial temperature = 25°C (25+273 = 298 K)

Initial volume = 4.5 L

Final temperature = ?

Final volume = 9.0 L

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂ = T₁V₂/V₁  

T₂ = 4.5 L × 298 K / 9.0 L

T₂ = 1341 L K / 9.0L

T₂ = 149 K

4 0
3 years ago
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