Problem: If you push an object with a constant force of 100 N over a 10-meter distance. How much energy transfer occurs on the o
1 answer:
The energy transferred on the object is 1000 Joules.
Given:
An object on which a constant force of 100 N was applied to displace it over a distance of 10 meters.
To find:
The energy transfer occurs on the object.
Solution
The force applied on the object = F = 100 N
The displacement of the object = d = 10 m
The energy transferred on the object or work done is given by:
The energy transferred on the object is 1000 Joules.
Learn more about work done here:
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The freezing point of a solution containing 5. 0 grams of KCl and 550.0 grams of water is - 0.45°C
Using the equation,
Δ = i
m
where:
Δ = change in freezing point (unknown)
i = Van't Hoff factor
= freezing point depression constant
m = molal concentration of the solution
Molality is expressed as the number of moles of the solute per kilogram of the solvent.
Molal concentration is as follows;
MM KCl = 74.55 g/mol
molal concentration =
molal concentration = 0.1219m
Now, putting in the values to the equtaion Δ = i
m we get,
Δ = 2 × 1.86 × 0.1219
Δ = 0.4536°C
So, Δ of solution is,
Δ = 0.00°C - 0.45°C
Δ = - 0.45°C
Therefore,freezing point of a solution containing 5. 0 grams of KCl and 550.0 grams of water is - 0.45°C
Learn more about freezing point here;
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Answer: -64.1 kJ.
Explanation:
According to first law of thermodynamics:
=Change in internal energy
q = heat absorbed or released
w = work done or by the system
w = work done by the system= {Work is done by the system is negative as the final volume is greater than initial volume}
w = -855 Joules = 0.855 kJ (1kJ=1000J)
q = -65.0 kJ {Heat released by the system is negative}
Thus the change internal energy (ΔE) for a system that is giving off 65.0 kJ of heat and is performing 855 J of work on the surroundings is -64.1 kJ.