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Answer: Always ask. ...
Put your weights back. ...
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Clean up after yourself (and, if you have to, other patrons). ...
Selfies: Try to be discreet about them. ...
Personal space: respect it. ...
Don't hog the equipment.
Supposing there's no air
resistance, horizontal velocity is constant, which makes it very easy to solve
for the amount of time that the rock was in the air.
Initial horizontal
velocity is: <span>
cos(30 degrees) * 12m/s = 10.3923m/s
15.5m / 10.3923m/s = 1.49s
So the rock was in the air for 1.49 seconds. </span>
<span>
Now that we know that, we can use the following kinematics
equation:
d = v i * t + 1/2 * a * t^2
Where d is the difference in y position, t is the time that
the rock was in the air, and a is the vertical acceleration: -9.80m/s^2. </span>
<span>
Initial vertical velocity is sin(30 degrees) * 12m/s = 6 m/s
So:
d = 6 * 1.49 + (1/2) * (-9.80) * (1.49)^2
d = 8.94 + -10.89</span>
d = -1.95<span>
<span>This means that the initial y position is 1.95 m higher than
where the rock lands. </span></span>
Answer:
The smallest possible beat frequency when B and C are sounded together is 3 Hz
Explanation:
Given;
the beat frequency of A and B = 2 Hz
the beat frequency of A and C = 5 Hz
Beat frequency is equal to the difference in frequency of the two notes that interfere to produce the beats.

Therefore, the smallest possible beat frequency when B and C are sounded together is 3 Hz