Which substances would be liquids at room temperature?

When do we classify a disease as epidemic

djyliett [7]

Explanation:

An epidemic (from Greek ἐπί epi "upon or above" and δῆμος demos "people") is the rapid spread of disease to a large number of people in a given population within a short period of time.

3 0

3 years ago

Read 2 more answers

What are two things in nature that solar energy powers?

adell [148]

Answer: light and heat

Explanation:Our sun is the source of all life on Earth, and solar energy is useful to us in many different ways. The sun creates two main types of energy - light and heat - that we can harness for many activities ranging from photosynthesis in plants to creating electricity with photovoltaic (PV) cells to heating water and food.

5 0

3 years ago

Two moles of gas A spontaneously convert to 3 moles of gas b in a container where the temperature and pressure are held constant

erica [24]

At constant temperature and pressure, If the amount of gas increases to the given value, its volume also increases to 20.85L.

<h3>What is Avogadro's law?</h3>

Avogadro's law states that "equal volumes of all gases, at the same temperature and pressure, have the same number of molecules."

It is expressed as;

V₁/n₁ = V₂/n₂

Given the data in the question;

Initial amount of gas n₁ = 2moles

Initial volume v₁ = 13.9L

Final amount of gas n₁ = 3moles

Final volume v₂ = ?

V₁/n₁ = V₂/n₂

V₁n₂ = V₂n₁

V₂ = V₁n₂ / n₁

V₂ = (13.9L × 3moles) / 2moles

V₂ = 41.7molL / 2mol

V₂ = 20.85L

At constant temperature and pressure, If the amount of gas increases to the given value, its volume also increases to 20.85L.

Learn more about Avogadro's law here: brainly.com/question/15613065

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4 0

2 years ago

enzyme‑catalyzed, single‑substrate reaction E + S − ⇀ ↽ − ES ⟶ E + P . The model can be more readily understood when comparing t

laila [671]

Complete Question

The complete question is shown on the first uploaded image

Answer:

[S]<<KM | [S]=KM | [S]>>KM | Not true

____________ | Half of the active | Reaction rate is | Increasing

$[E_{free}]$ is about | sites are filled of | independent of | $[E_{Total}]$ will

equal to $[E_{total}]$ . | | [S] | lower KM

_____________________________________________|____________

[ES] is much | | Almost all active

lower than | | sites are filled

$[E_{free}]$ | |

Explanation:

Generally the combined enzyme $[ES]$ is mathematically represented as

$[ES] = \frac{[E_{total}][S]}{K_M + [S]}----(1)$

for Michaelis-Menten equation

Where $[S]$ is the substrate concentration and $K_M$ is the Michaelis constant

Considering the statement $[S] < < K_M$

Looking at the equation $[S]$ is denominator so it can be ignored(it is far too small compared to $K_M$ ) hence the above equation becomes

$[ES] = \frac{[E_{total}][S]}{K_M}$

Since $[S]$ is less than $K_M$ it means that $\frac{[S]}{K_M} < < 1$

so it means that $[ES] < < [E_{total}]$

What this means is that the number of combined enzymes $[ES]$ i.e the number of occupied site is very small compared to the the total sites $[E_{total}]$ i.e the total enzymes concentration which means that the free sites [ $E_{free}]$ i.e the concentration of free enzymes is almost equal to $[E_{total}]$

Considering the second statement

$[S] = K_M$

So this means that equation one would now become

$[ES] = \frac{[E_{total}][S]}{2[S]} = \frac{[E_{total}]}{2}$

So this means that half of the active sites that is the total enzyme concentration are filled with S

Considering the Third Statement

$[S] >>K_M$

In this case the $K_M$ in the denominator of equation 1 would be neglected and the equation becomes

$[ES] = \frac{[E_{total}] [S]}{[S]} = [E_{total}]$

This means that almost all the sites are occupied with substrate

The rate of this reaction is mathematically defined as

$v =\frac{V_{max}[S]}{K_M [S]}$

Where v is the rate of the reaction(also know as the velocity of the reaction at a given time t) and $V_{max}$ is he maximum velocity of the reaction

In this case also the $K_M$ at the denominator would be neglected as a result of the statement hence the equation becomes

$v = \frac{V_{max}[S]}{[S]} = V_{max}$

So it means that the reaction does not depend on the concentration of substrate [S]

For the final statement(Not True ) it would match with condition that states that increasing $[E_{total}]$ will lower $K_M$

This is because $K_M$ does not depend on enzyme concentration it is a property of a enzyme

7 0

3 years ago

How many levels will argon have?

Varvara68 [4.7K]

They have about 4 or 6

7 0

3 years ago