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3 years ago

Please I don't understand any of this. If you can answer by midnight this is due tomorrow, April 29th

Chemistry

1 answer:

kupik [55]3 years ago

7 0

Answer:

(2) Adding more O2(g) would shift the equilibrium to the right because a higher concentration of oxygen is offered than its initial position, therefore more products have to be yielded to maintain equilibrium.

Explanation:

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Minerals are grouped according to their

tino4ka555 [31]

Answer:

chemical composition

3 0

4 years ago

find the mass of 1 mole of cuprous oxide, or cu2o. assume the atomic mass of copper is 64 and oxygen is 16.

S_A_V [24]

The mass of a mole of Cu₂O is basically the molar mass of this compound. To find this, add the molar mass of each atom in the compound together. Therefore you will get 62x2 + 16 = 140 grams

7 0

4 years ago

A volatile organic liquid with known molecular weight is added to a vapor density flask which has a known volume. The flask is h

kakasveta [241]

Answer: Mass of the condensed vapor is 21.35 grams.

Explanation: As a gas, the Ideal Gas Law can be used to determine how many mols there are in the flask on the conditions described in question.

Temperature in K: 273 + 99.3 = 372.4K

Pressure in mmHg: P = 760.5 mmHg

Volume in L: V = 496.3. $10^{-3}$ = 0.5 L

Universal Constant of Gases in mmHg: R = 62.36 L.mmHg.K⁻¹.mol⁻¹

PV = nRT

n = $\frac{PV}{RT}$

n = $\frac{760.5.0.5}{62.36.372.4}$

n = 0.1625

To determine the mass in grams:

n = $\frac{m}{M}$

m = nM

m = 0.1625.131.4

m = 21.35

On the conditions cited above, there are <u>21.35 grams</u> of the unknown condensed vapor

3 0

3 years ago

Are these answers correct? I’m a little unsure

Naily [24]

Answer:

yes I think that they are correct

8 0

3 years ago

Rank the following gases in order of decreasing rate of effusion. Rank from the highest to lowest effusion rate. To rank items a

Alinara [238K]

Answer:

H2, He, PH3, F2, C5H10

Explanation:

From Graham's law, we understood that lighter gas will diffuse faster than heavier gas under same condition. Graham's law of diffusion states as follow:

The rate (R) of diffusion of a gas is inversely proportional to the square root of its density (D) provided temperature and pressure remains constant. Mathematically, it is represented as:

R & 1/√D

Recall:

Molar Mass (M) = 2 x vapour density (D)

M = 2D

R & 1/√M

From the above, we can see that the rate is inversely proportional to the square root of the molar mass of substance. This implies that lighter gas will diffuse faster.

Now, to rank the above from the highest to rate rate of effusion, let us determine the molecular weight of each substance. This is illustrated below:

Molar Mass of F2 = 19 x 2 = 38g/mol

Molar Mass of He = 4g/mol

Molar Mass of C5H10 = (12X5) + (10X1) = 70g/mol

Molar Mass of H2 = 2x1 = 2g/mol

Molar Mass of PH3 = 31 + (3x1) = 34g/mol

Now, we can rank the substance beginning from the highest to the lowest rate of effusion as follow:

Substance >> Molar Mass >> Rank

H2 >>>>>>>>> 2g/mol >>>>>> 1

He >>>>>>>>> 4g/mol >>>>>> 2

PH3 >>>>>>>> 34g/mol >>>>> 3

F2 >>>>>>>>>> 38g/mol >>>> 4

C5H10 >>>>>> 70g/mol >>>> 5

3 0

3 years ago