Question

A forward-biased silicon diode is connected to a 12.0-V battery through a resistor. If the current is 12 mA and the diode potential difference is 0.70 V, what is the resistance?

Answer 1

To solve this problem we will use the concepts related to Ohm's law for which voltage, intensity and resistance are related.

Mathematically this relationship is given as

$V = IR \rightarrow R= \frac{V}{I}$

Where,

V= Voltage

I = Current

R = Resistance

The value of the given voltage is 12V, while the current is 12mA, therefore the resistance would be

$R = \frac{12}{12*10^{-3}}$

$R = 1000 \Omega$

Therefore the resistance is $1000\Omega$