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kkurt [141]
3 years ago
6

A forward-biased silicon diode is connected to a 12.0-V battery through a resistor. If the current is 12 mA and the diode potent

ial difference is 0.70 V, what is the resistance?
Physics
1 answer:
MissTica3 years ago
3 0

To solve this problem we will use the concepts related to Ohm's law for which voltage, intensity and resistance are related.

Mathematically this relationship is given as

V = IR \rightarrow R= \frac{V}{I}

Where,

V= Voltage

I = Current

R = Resistance

The value of the given voltage is 12V, while the current is 12mA, therefore the resistance would be

R = \frac{12}{12*10^{-3}}

R = 1000 \Omega

Therefore the resistance is 1000\Omega

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