Question

the lengths of the sides of a triangle are 2m , 4.8m and 5.2m. Determine the area of the triangle please help me​

Answer 1

To find the area of a triangle with the given sides a, b and c we use an expression,

Area = $\sqrt{s(s-a)(s-b)(s-c)}$

Where, $s=\frac{a+b+c}{2}$

By applying this formula area of the given triangle is 4.8 m².

Side lengths of the triangle are 2m, 4.8m and 5.2m

Therefore, $s=\frac{2+4.8+5.2}{2}$

$s=6$

Now substitute these values in the formula,

Area = $\sqrt{6(6-2)(6-4.8)(6-5.2)}$

        = $\sqrt{6(4)(1.2)(0.8)}$

        = 4.8 m²

  Therefore, area of the triangle with the given sides is 4.8 m².

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Answer 2

Answer:

Area of the triangle is 4.8 square meters using heron's formula to find area of triangle.

Step-by-step explanation:

Formula to find area of triangle when three sides were given is

Semi perimeter s =$\frac{a+b+c}{2}$

Where 'a' , 'b' and 'c' are side lengths of the triangle.

Area =$\sqrt{s(s-a)(s-b)(s-c)}$

Here, let a=2, b=4.8 and c=5.2

So, semi perimeter s=$\frac{2+4.8+5.2}{2}$

Simplify it

s=6

Now use area formula to find area of the triangle.

A=$\sqrt{6(6-2)(6-4.8)(6-5.2)}$

Simplify it

A=$\sqrt{6(4)(1.2)(0.8)}$

A=$\sqrt{23.04}$

A=4.8 square meters.