Question

Two balloons are charged with an identical quantity and type of charge: -6.25 x 10-6 C. They are held apart at a separation distance of 0.02 m. Determine the magnitude of the electrical force of repulsion between them

Answer 1

Answer:

The electric force between them is 878.9 N

Explanation:

Given:

Identical charge $q = -6.25 \times 10^{-6}$C

Separation between two charges $r = 0.02$ m

For finding the electrical force,

According to the coulomb's law

   $F = \frac{k q^{2} }{r^{2} }$

Here, force between two balloons are repulsive because both charges are same.

Where $k = 9 \times 10^{9}$

   $F = \frac{9 \times 10^{9} \times (-6.25 \times 10^{-6} )^{2} }{4 \times 10^{-4} }$

   $F = 878.9$ N

Therefore, the electric force between them is 878.9 N