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Gnesinka [82]
3 years ago
9

Two balloons are charged with an identical quantity and type of charge: -6.25 x 10-6 C. They are held apart at a separation dist

ance of 0.02 m. Determine the magnitude of the electrical force of repulsion between them
Physics
1 answer:
steposvetlana [31]3 years ago
8 0

Answer:

The electric force between them is 878.9 N

Explanation:

Given:

Identical charge q = -6.25 \times 10^{-6}C

Separation between two charges r = 0.02 m

For finding the electrical force,

According to the coulomb's law

   F = \frac{k q^{2} }{r^{2} }

Here, force between two balloons are repulsive because both charges are same.

Where k = 9 \times 10^{9}

   F = \frac{9 \times 10^{9} \times (-6.25 \times 10^{-6} )^{2}  }{4 \times 10^{-4} }

   F = 878.9 N

Therefore, the electric force between them is 878.9 N

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