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3 years ago

What is density of gold

Physics

2 answers:

Mademuasel [1]3 years ago

4 0

Answer:

the density of gold is 19.3 g/cc

ivann1987 [24]3 years ago

4 0

Answer:

Gold has density of 19.3 g/cc.

Explanation:

The density of an element is the amount of mass it has per unit volume.

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Determine the length of the tungsten filament in a 100 watt lightbulb given: (i) the resistivity of tungsten is 5.6 × 10−8 Ω · m

svetoff [14.1K]

Answer:

0.34148 m

Explanation:

$\rho$ = Resistivity of tungsten = $5.6\times 10^{-8}\ \Omega m$

d = Diameter = 0.0018 inch

r = Radius = $\dfrac{r}{2}=\dfrac{0.0018}{2}=0.0009\ in$

$r=0.0009\times 0.0254=0.00002286\ m$

$\alpha$ = Temperature coefficient of tungsten = $0.0045 /^{\circ}C$

Power is given by

$P=\dfrac{V^2}{R}\\\Rightarrow R=\dfrac{V^2}{P}\\\Rightarrow R=\dfrac{120^2}{100}\\\Rightarrow R=144\ \Omega$

We have the equation

$R_2=R_1[1+\alpha(T_2-T_1)]\\\Rightarrow R_1=\dfrac{R_2}{1+\alpha(T_2-T_1)}\\\Rightarrow R_1=\dfrac{144}{1+0.0045(2550-25)}\\\Rightarrow R_1=11.64812\ \Omega$

Resistance is given by

$R=\rho\dfrac{l}{A}\\\Rightarrow l=\dfrac{RA}{\rho}\\\Rightarrow l=\dfrac{11.64812\times \pi (0.00002286)^2}{5.6\times 10^{-8}}\\\Rightarrow l=0.34148\ m$

The length of the filament is 0.34148 m

7 0

3 years ago

What type of change occurs when water changes from a solid to a liquid

Jobisdone [24]

What type of change occurs when water changes from solid to a liquid a phase change a physical change and irreversible change both A and the

8 0

3 years ago

With the aid of a string, a gyroscope is accelerated from rest to 16 rad/s in 0.40 s. what is its angular acceleration in rad/s2

vovikov84 [41]

Angular acceleration = (change in angular speed) / (time for the change)

Change in angular speed = (ending speed) minus (starting speed)

Change in angular speed = (16 rad/s) - (zero) = 16 rad/s .

Angular acceleration = (16 rad/s) / (0.4 s)

(Average) angular acceleration = 40 rad/s²

4 0

3 years ago

PLEASE HELP!!!! Thank you!

V125BC [204]

it would be a chain reaction and a wave

6 0

4 years ago

An electron moves through a uniform electric field vector E = (2.80î + 5.20ĵ) V/m and a uniform magnetic field vector B = 0.400k

alina1380 [7]

Answer:

1.758820×10^11(-2.5i-0.8j) m/s^2

Explanation:

From the question, the parameters given are; E=(2.80i+ 5.20j) v/m, a uniform magnetic field,B= 0.400K T, acceleration, a= ??? and velocity vector, v= 11.0i metre per seconds (m/s)...

We can solve this problem using the formula below;

Ma= q[E+V × B] ---------------(1).

Note: q is negative, m= mass of electron.

Making acceleration,a the subject of the formula and substituting the parameters into equation (1);

a= -e/m × (2.5i + 5.2j +11.0i × 0.400K)

a= -e/m × (2.5i+5.2j-4.4j)

a= e/m × (-2.5i - 0.8j)

e/m= 1.758820×10^11 c/kg

Therefore, slotting in the value of charge to mass(e/m) ratio;

a= 1.7588×10^11×(-2.5i-0.8j) m/s^2

7 0

3 years ago