33
60
---
1980
33*60sec = 1980 sec for comparison
Answer:
–8.35 m/s²
Explanation:
We'll begin by converting 104 km/h to m/s. This can be obtained as follow:
3.6 Km/h = 1 m/s
Therefore,
104 km/h = 104 km/h × 1 m/s / 3.6 Km/h
104 km/h = 28.89 m/s
Thus, 104 km/h is equivalent to 28.89 m/s.
Finally, we shall determine the deceleration of the car. This can be obtained as follow:
Initial velocity (u) = 28.89 m/s
Final velocity (v) = 0 m/s
Distance (s) = 50 m
Deceleration (a) =?
v² = u² + 2as
0² = 28.89² + (2 × a × 50)
0 = 834.6321 + 100a
Collect like terms
0 – 834.6321 = 100a
–834.6321 = 100a
Divide both side by 100
a = –834.6321 / 100
a = –8.35 m/s²
Thus, the deceleration of the car is –8.35 m/s².
Change in speed = (acceleration) x (time)
4 minutes = 240 seconds
Change in speed = (40 m/s²) x (240 seconds)
Change in speed = <em>9,600 m/s</em>
What you're actually describing here is a car pulling 4 G's for 4 minutes, and ending up going 21,475 miles per hour.
The driver would definitely NOT get a speeding ticket, because nobody could catch him.
Also, his car would heat up and shoot flames from atmospheric friction.
(He could avoid this with some fancy steering, leave the atmosphere, and end up in low-Earth-orbit.)
Actually, I hope there's nobody in the car. His experience wouldn't be pretty.
Calculate the circumference of the circular path of the wheel by the equation,
C = 2πr
where C is the circumference,
r is the radius
Substituting the known values,
C = 2(π)(0.487 m) = 3.06 m
Then, period of the motion will be determined by dividing the number of rotations done,
T = (3.06 m) / (5.75 /s) = 0.53 s
<em>ANSWER: 0.53 s</em>
Answer:
1 μC extra charge will be flow here
Explanation:
Given data
battery V1 = 4.0 V
flows Q1 = 6.0 μC
replace battery V2 = 7.0 V
to find out
what happen if we replace battery
solution
we apply here principal of capacitor
that is Q directly proportional voltage
so we say Q2/Q1 = V2/ V1
put all value here
Q2/Q1 = V2/ V1
Q2/6 = 7/ 6
Q2 = 7
so we see here 7 μC will be flow
and Q = Q2 - Q1 = 7 - 6 = 1 μC
so we also say that 1 μC extra charge will be flow here
