Answer:
No
Explanation:
You could try to give it enough to fill all valence electrons in all of the atoms in the conductor, but practically this could not be achieved.
Kinetic energy = 1/2 * mass * velocity^2
In this case,
KE = 1/2 * 1569 kg * (15 (m/s))^2 = 176,5 kN
Answer:
10 m
Explanation:
5 m/s * 2 s = 10 meters ( see how the ' s ' cancels out?)
Answer:
Force of 6250N is required to slow down the body to zero.
Explanation:
Speed(V)=20m/s
Initial speed (u) =0m/s
Mass(M)=1000kg
Time(t)=3.2seconds
Using first equation of motion to find the acceleration of the body:
V=U + at
20m/s=0 + a*3.2s
Therefore, a=(20m/s)/3.2s
a=6.25m/s^2
To find the force required to stop the body or get it down to zero:
Force(F)=mass x acceleration
F=(1000kg)*(6.25m/s^2)
F=6250N.
Therefore a force of 6250N is required to slow it down.
Answer:
Explanation:
Note : the questions do not come in the right order.
Data:
Mass = 0.0518kg
Velocity = 45 m / s
Distance (s) = 0.44m
C) what's the acceleration on the ball?
Using equation of motion,
V² = u² + 2as
V² - u² = 2as
a = (v² - u²) / 2s
a = (45² - 0) / 2 * 0.44 [the ball was at rest]
a = 2025 / 0.88
a = 2301.136m/s²
D) The net force on the ball?
Force = mass * acceleration
F = m*a
F = 0.0518 * 2301.136
F = 119.199N
The force acting on the ball was 133.465N
F = 133.47N
b) time period the ball was struck.
From the relationship between impulse and momentum,
Ft = m * v
133.47 * t = 0.058 * 45
t = 2.61 / 133.47
t = 0.01955s
a) average velocity (V) = total distance covered / total time taken
V = s / t
V = 0.44 / 0.01955
V = 22.50m/s.
e) if the ball was heavier and still experienced the same velocity, the applied would've been lesser than before.
