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Digiron [165]
4 years ago
9

A system of pulleys is used to raise a load of bricks that weighs 1,700 newtons. The force applied to the pulley is 340 newtons.

What’s the mechanical advantage of this machine?
Physics
2 answers:
Trava [24]4 years ago
8 0
According to the Free Body Diagram of pulley system:

MA = W/T = n.

Here, MA is the mechanical advantage, W is the load, T is the tension, and n is the number of sections of rope supporting the load.

Let's calculate the ratio: 1700/340 = 5

Which means the T = 1/5 W, it can be achieved by compound pulley system with 4 or 5 pulleys.

So MA = 5, this is your answer. 
ludmilkaskok [199]4 years ago
7 0

Answer:   5

SUB TO MR BEAST!

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The black board appears black because:
marishachu [46]

Answer:

I think its C All visible light wavelengths (ROYGBV) are absorbed by the board

8 0
3 years ago
If the 0.09-mm-diameter tungsten filament in a light bulb is to have a resistance of 0.11 Ω at 20∘C, how long should it be?
skad [1K]

Answer:

Length L=0.0125 m

Explanation:

Given data

Resistance R=0.11Ω

Temperature T=20°C

Resistivity of tungsten at 20°C p=5.6×10⁻⁸Ω.m²

Radius of filament r=0.09/2 =0.045 mm =0.045×10⁻³m

To find

Length of filament L

Solution

The Cross section of area of filament is given as:

A=\pi r^{2}\\ A=\pi (0.045*10^{-3})^{2}\\A=6.3585*10^{-9}m^{2}

The Resistance of a material is given as:

R=p\frac{L}{A} \\L=\frac{AR}{p}\\ L=\frac{(6.3585*10^{-9})(0.11)}{5.6*10^{-8}}\\L=0.125m

6 0
3 years ago
The lens-makers’ equation applies to a lens immersed in a liquid if n in the equation is replaced by n2/n1. Here n2 refers to th
pickupchik [31]

Answer:

a

The focal length of the lens in water is  f_{water} = 262.68 cm

b

The focal length of the mirror in water is  f =79.0cm

Explanation:

From the question we are told that

    The index of refraction of the lens material = n_2

    The index of refraction of the medium surrounding the lens = n_1

 

The lens maker's formula is mathematically represented as

            \frac{1}{f} = (n -1) [\frac{1}{R_1} - \frac{1}{R_2}  ]

Where f is the focal length

            n is the index of refraction

            R_1 and R_2 are the radius of curvature of sphere 1 and 2 of the lens

From the question When the lens in air  we have  

           \frac{1}{f_{air}} = (n-1) [\frac{1}{R_1} - \frac{1}{R_2}  ]

    When immersed in liquid the formula becomes

          \frac{1}{f_{water}} = [\frac{n_2}{n_1} - 1 ] [\frac{1}{R_1} - \frac{1}{R_2}  ]

The ratio of the focal length of the the two medium is mathematically evaluated as

           \frac{f_water}{f_{air}} = \frac{n_2 -1}{[\frac{n_2}{n_1} - 1] }

From the question

      f_{air }= 79.0 cm

       n_2 = 1.55

and the refractive index of water(material surrounding the lens) has a constant value of  n_1 = 1.33

         \frac{f_{water}}{79}  = \frac{1.55- 1}{\frac{1.55}{1.44}  -1}

           f_{water} = 262.68 cm

b

The focal length of a mirror is dependent on the concept of reflection which is not affected by medium around it.

   

7 0
3 years ago
Where is visible light found on the electromagnetic spectrum?
torisob [31]
<span>The common designations are radio waves, microwaves, infrared (IR), visible light, ultraviolet (UV), X-rays and gamma-rays. Visible light falls in the rangeof the EM spectrum between infrared (IR) and ultraviolet (UV).</span>
8 0
3 years ago
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Which physical property refers to the temperature at which a substance in a solid-state transforms to a liquid state?
solmaris [256]

Answer:

C: Melting point

Explanation:

3 0
3 years ago
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