Answer:
Fd
Explanation:
Work is force times distance. If you push on an object really hard but it does not budge, you have still performed no work on it, because anything times zero is still zero.
Answer:
Explanation:
Based on the wave model of light, physicists predicted that increasing light amplitude would increase the kinetic energy of emitted photoelectrons, while increasing the frequency would increase measured current.
Contrary to the predictions, experiments showed that increasing the light frequency increased the kinetic energy of the photoelectrons, and increasing the light amplitude increased the current.
Based on these findings, Einstein proposed that light behaved like a stream of particles called photons with an energy of \text{E}=h\nuE=hνstart text, E, end text, equals, h, \nu.
The work function, \PhiΦ\Phi, is the minimum amount of energy required to induce photoemission of electrons from a metal surface, and the value of \PhiΦ\Phi depends on the metal.
The energy of the incident photon must be equal to the sum of the metal's work function and the photoelectron kinetic energy:
Answer:
481.76 J/mol
133.33 K
Explanation:
= Avogadro's number = 
Change in enthalpy is given by

Entropy is given by

Latent heat of fusion is given by

The latent heat of fusion is 481.76 J/mol
Melting point is given by

Melting occurs at 133.33 K
Answer:
La velocidad media es 5
, que equivale a 1.389 
Explanation:
La velocidad es una magnitud física que expresa la relación entre el espacio recorrido por un objeto y el tiempo empleado para ello.
La velocidad media relaciona el cambio de la posición con el tiempo empleado en efectuar dicho cambio. Por lo que se calcula como la distancia recorrida por un objeto dividido por el tiempo transcurrido:

En este caso:
- distancia= 10 km= 10,000 m (siendo 1 km= 1,000 m)
- tiempo= 2 h= 7,200 s (siendo 1 h= 3,600 s)
Entonces, reemplazando en la definición de velocidad media:

Resolviendo se obtiene:

<u><em>La velocidad media es 5 </em></u>
<u><em>, que equivale a 1.389 </em></u>
<u><em></em></u>