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photoshop1234 [79]

3 years ago

11

Animals communicate for various reasons, but one main reason is for reproduction. In what ways do animals communicate with other

members of their species with the goal of reproduction

1 answer:

Natasha_Volkova [10]3 years ago

6 0

Animals communicate using signals, which can include visual; auditory, or sound-based; chemical, involving pheromones; or tactile, touch-based, cues

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A Sattelite is a (n)

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Satellite, also called artificial satellite, is a computer-controlled machine or objects that is launched into the space by a rocket, called the launch vehicle and placed in the orbit of a celestial object.

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4 years ago

What is an ecosystem?<br> living environment by the way

MAVERICK [17]

An ecosystem is a lot of things and places that need each other to survive

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4 years ago

How many significant figures are in 0.00102?

zaharov [31]

Answer:

3

Explanation:

102 are significant figures

7 0

2 years ago

Read 2 more answers

Solve the following problem. Give your answer to the correct number of significant figures. a. 20.0 meters x 0012.65 meters b. 0

Nezavi [6.7K]

Explanation:

For multiplication or division, the rule is to count the number of significant figures in each number being multiplied or divided and then limit the significant figures in the answer to the lowest count.

a. 20.0 meters x 0012.65 meters

The numbers are;

20.0 (3 s.f) and 12.65 (4 s.f)

The multiplication gives; 253

Since 253 is already in 3 s.f, that's the answer.

b. 002.5 × 103 meters + 3.50 × 102 meters

The numbers are;

002.5 (2 s.f), 103 (3 s.f), 3.50 (3 s.f) and 102 (3 s.f)

002.5 × 103 = 257.5 = 260 (2 s.f)

3.50 × 102 = 357 = 360 (2 s.f)

260 + 360 = 620

4 0

3 years ago

The stopcock connecting a 3.06 L bulb containing methane gas at a pressure of 9.61 atm, and a 6.65 L bulb containing oxygen gas

Contact [7]

Answer : The final pressure in the system is 4.22 atm.

Explanation :

First we have to calculate the moles of methane.

$PV=n_1RT$

where,

P = pressure of gas = 9.61 atm

V = volume of gas = 3.06 L

T = temperature of gas = T

$n_1$ = number of moles of methane gas = ?

R = gas constant

Now put all the given values in the ideal gas equation, we get:

$(9.61atm)\times (3.06L)=n_1\times RT$

$n_1=\frac{29.4}{RT}$

Now we have to calculate the moles of oxygen gas.

$PV=n_2RT$

where,

P = pressure of gas = 1.75 atm

V = volume of gas = 6.65 L

T = temperature of gas = T

$n_2$ = number of moles of oxygen gas = ?

R = gas constant

Now put all the given values in the ideal gas equation, we get:

$(1.75atm)\times (6.65L)=n_2\times RT$

$n_2=\frac{11.6}{RT}$

Now we have to determine the final pressure in the system after mixing the gases.

$P_{total}=(n_1+n_2)\times \frac{RT}{V_{total}}$

where,

$P_{total}$ = final pressure of gas = ?

$V_{total}$ = final volume of gas = (3.06 + 6.65)L = 9.71 L

T = temperature of gas = T

R = gas constant

Now put all the given values in the ideal gas equation, we get:

$P_{total}=(\frac{29.4}{RT}+\frac{11.6}{RT})\times \frac{RT}{9.71L}$

$P_{total}=4.22atm$

Therefore, the final pressure in the system is 4.22 atm.

4 0

3 years ago