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natali 33 [55]
2 years ago
15

If the loop is then converted into a rectangular loop measuring 2.1cm on its shortest side in 6.50ms, and the average emf induce

d across the loop is 14.7V during this time period, what is A.the strength of the B-field
Physics
1 answer:
kaheart [24]2 years ago
5 0

Answer:

B =34.5T

Explanation:

Given E = 14.7V, L= 2.1cm = 0.021m, t = 6.50ms = 6.50×10-³s

A = L² = 0.021² = 4.41×10-⁴m²

ω = 2π/t = 2π/(6.50×10-³) = 966.64rad/s

E = ωBA

B = E/ωA = 14.7/(966.64×4.41×10-⁴)

B = 34.5T

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Four power transistors, each dissipating 12 W, are mounted on a thin vertical aluminum plate 22 cm 3 22 cm in size. The heat gen
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Answer:

The temperature of the Aluminium plate 44.84⁰C

Explanation:

Number of transistors = 4

Since the heat dissipated by each transistor is 12W

Total heat dissipated, Q = 4 * 12 = 48 W

Q = 48 W

Cross sectional Area of the Aluminium plate, A = 2(l * b)

l = Length of the aluminium plate = 22 cm = 0.22 m

b = width of the aluminium plate = 22 cm = 0.22 m

A =2( 0.22 * 0.22 )

A = 0.0968 m²

From the heat balance equation, Q = hAΔT

h = 25 W/m²·K

A = 0.0968 m²

ΔT = T - T(air)

T(air) = 25°C

ΔT = T - 25°C

Q = 25 * 0.0968 * (  T - 25)

Q = 2.42 (T - 25)

Substitute Q = 48 into the equation above

48 =  2.42 (T - 25)

T - 25 = 19.84

T = 25 + 19.84

T = 44.84 ⁰C

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