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natali 33 [55]
3 years ago
15

If the loop is then converted into a rectangular loop measuring 2.1cm on its shortest side in 6.50ms, and the average emf induce

d across the loop is 14.7V during this time period, what is A.the strength of the B-field
Physics
1 answer:
kaheart [24]3 years ago
5 0

Answer:

B =34.5T

Explanation:

Given E = 14.7V, L= 2.1cm = 0.021m, t = 6.50ms = 6.50×10-³s

A = L² = 0.021² = 4.41×10-⁴m²

ω = 2π/t = 2π/(6.50×10-³) = 966.64rad/s

E = ωBA

B = E/ωA = 14.7/(966.64×4.41×10-⁴)

B = 34.5T

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bagirrra123 [75]

Answer:

Iron

Explanation:

5 0
3 years ago
sound is a longitudinal wave, and its speed depends on the medium through which it propagates. in air, sound travels at 343 m/s
melomori [17]

The speed of the sound wave in the medium, given the data is 3900 m

<h3>Velocity of a wave </h3>

The velocity of a wave is related to its frequency and wavelength according to the following equation:

Velocity (v) = wavelength (λ) × frequency (f)

v = λf

With the above formula, we can obtain the speed of the sound wave. Details below:

<h3>How to determine speed of the sound wave</h3>

The speed of the wave can be obtained as illustrated below:

  • Frequency (f) = 600 Hz
  • Wavelength (λ) = 6.5 m
  • Velocity (v) =?

v = λf

v = 6.5 × 600

v = 3900 m

Thus, the speed of the sound wave in the medium is 3900 m

Learn more about wave:

brainly.com/question/14630790

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8 0
1 year ago
A ball is thrown upwards and returns to the same location. Compared with its initial speed its speed when it returns is about___
Strike441 [17]

Answer:

Explanation:

Let the ball is thrown upwards with speed u and reaches upto height h.

Use III equation of motion

v^{2}=u^{2}-2gh

here, final velocity v = 0

So, u = \sqrt{2gh}

Now as the ball reaches the maximum height, it starts falling freely. Let it strkes with the ground with velocity v'.

v'^{2}=u^{2}-2gh

here, u = 0

So, v' = \sqrt{2gh}

It means the velocity is same as the velocity of projection.

4 0
3 years ago
Determine the gravitational force of attraction experienced by a two 5.00 kilogram masses separated by a distance of 2.5 meters.
drek231 [11]
The gravitational force between two objects may be calculated through the equation,
                                     F = Gm₁m₂ / d²
where G is 6.67 x 10^-11 m³/s²kg
Substituting the known values to the equation,
                        F = (6.67 x 10^-11 m³/s²kg)(5.0 kg)(5.0 kg) / (2.5 m)²
                                     F = 2.668 x 10^-10 N
4 0
3 years ago
Plz help!!!!!!! will mark as brainliest!!!!!!!
jolli1 [7]
C is what I think the answer is:)
7 0
3 years ago
Read 2 more answers
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