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mihalych1998 [28]
3 years ago
7

What causes atoms to form covalent bonds?

Chemistry
1 answer:
tino4ka555 [31]3 years ago
6 0

Sharing of valence electrons.

Explanation:

In a covalent bonds, there is sharing of the valence electrons used in bonding between the two combining species.

The atoms taking part do not have a wide electronegativity difference between them and so they share the valence electrons to complete their octet and ensure their stability.

  • For the formation of this bond type, each of the atom requires a odd or unpaired electrons.
  • Covalent bonds are formed between atoms having zero or very small electronegativity difference.

Learn more:

Covalent bonds brainly.com/question/10903097

#learnwithBrainly

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Identify the molecule with the highest boiling point. NH3 CO2 C2H2 C3H8
Black_prince [1.1K]

Answer:

NH3

Explanation:

NH3 molecules make strong intermolecular H bondings and also because of the increase in the size of atomic radius.

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4 years ago
How many elements in C6H12O6
zysi [14]

Answer:

3

Explanation:

there are 3 different elements in sugar. just add up all the letters you see

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3 years ago
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How many mL of 0.150 M HF solution are required to produce 0.0370 moles of HF
stealth61 [152]

Answer:

247 ml

Explanation:

How many mL of 0.150 M HF solution are required to produce 0.0370 moles of HF 0.150 moles/ liter = 0.150/1000 moles/ml =0.000150 moles/ml

0.000150 x ? = 0.0370 moles HF

? = 0.0370/0.000150 = 247 ml

check

247 ml = 247/1000 L = 0.247

(0.247) x (0.150) =0.370 check

4 0
2 years ago
A _____ bond is a type of chemical bond where a pair of electrons is unequally shared between two atoms. As a result, one end of
insens350 [35]

Polar Covalent Bond

This bond exists when atoms that have different electronegativities share electrons in a covalent bond, the electrons are not transferred from one atom to the other as in the case of ionic bond.

8 0
4 years ago
What is the conjugate acid of each of the following? What is the conjugate base of each?
Lilit [14]

Answer:

a. H₂O (conjugate acid) ; b. OH⁻ (conjugate base), H₃O⁺ (conjugate acid) ; c. H₂CO₃ (conjugate acid), CO₃⁻² (conjugate base) ; d. NH₄⁺ (conjugate strong acid) e. H₂SO₄ (conjugate acid), SO₄⁻² (conjugate base) ; f. No conjugate acid either base;  g. H₂S (conjugate acid), S⁻² (conjugate base);

h. H₄N₂ (conjugate base)

Explanation:

a.  OH⁻  +  H⁺  ⇄ H₂O

The hydroxide acts like a Bronsted Lory base, so it can catch a proton. Water will be the conjugate acid.

b. H₂O, is an amphoterus compound. It can act as an acid or a base. If it is a base, the conjugate acid is the H₃O⁺. If it is an acid, the conjugate base is the OH⁻.

c. HCO₃⁻  +  H⁺  ⇄  H₂CO₃

HCO₃⁻  +  H₂O  ⇄ CO₃⁻²  +  H₃O⁺

The bicarbonate is also amphoteric. When it catches the proton, the carbonic acid is the conjugate acid, cause it works as a base.

When the HCO₃⁻ (acid) release the proton, the conjugate base is the carbonate.

d. Ammonia is a weak base, so the conjugate strong acid is the ammonium.

NH₃ + H₂O  ⇄  NH₄⁺  +  OH⁻

e. Another amphoteric compound. The acid sulfate acts an acid and a base.

(like bicarbonate). When it is a base, the conjugate acid is the sulfuric acid, when it is an acid, the conjugate base is the sulfate.

HSO₄⁻  +  H₂O  ⇄  SO₄⁻²  +  H₃O⁺

HSO₄⁻  +  H⁺  ⇄  H₂SO₄

f. H₂O₂ does not recieve H⁺ or OH⁻, and it does not release H⁺. It is a neutral compound and it doesn't act as a base or acid.

g. HS⁻ is amphoterous.

HS⁻  +  H⁺  ⇄  H₂S

HS⁻  +  H₂O  ⇄  S⁻²  +  H₃O⁺

Same case as bicarbonate or acid sulfate.

h. H₅N₂⁺  +  H₂O  ⇄  H₄N₂  + H₃O⁺

Hidrazinium acts an acid, so, the conjugate base will be the hidrazine.

                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                           

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