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3 years ago

the electric charge remains at rest in a. static electricity, b. current electricity, c. none of these

Physics

1 answer:

Arturiano [62]3 years ago

6 0

Answer:

Option (a) is correct.

Explanation:

The electric charge is the inherent property of matter which appears due to the deficiency of charge or the excess number of electrons.

There are two types of charges, positive and negative.

When an object has deficiency of charge it becomes positive charge and when it gains some electrons, it becomes negative charge.

When the charge is in motion, it is called electric current and when the charge is at rest, it is called static current.

A charge at rest contributes the electric field only while the charge is in motion contributes the electric and magnetic field both.

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Determine the moment of the force at AAA about point PPP. Use a vector analysis and express the result in Cartesian vector form.

Dimas [21]

Answer:

τ = 0

Explanation:

At the moment it is defined

τ = F x r

In tete case they give us the strength and position in Cartesian form, so it is easier to solve the determinant

τ = $\left[\begin{array}{ccc}i&j&k\\F_{x}&F_{y}&F_{z}\\x&y&z\end{array}\right]$

Let's apply this expression to the exercise

a) P = (-6 i ^ -3j ^ -6 k ^) m

F = (-6 i ^ -3j ^ -6k ^) 103 N

τ = $\left[\begin{array}{ccc}i&j&k\\-6&-3&-6\\-6&-3&-6\end{array}\right]$

τ = i ^ (3 6 - 3 6) + j ^ (6 6 -6 6) + k ^ (6 3 - 3 6)

τ = 0

b) P = 24i ^ + 8j ^ + 9k ^

F = 24i + 8j + 9k

τ = i ^ (72-72) + j ^ (216-216) + k ^ (24 8 - 8 24)

τ = 0

c) P = -6i + 6j-4k

F = -6i + 6j-4k

τ = i ^ (24-24) + j ^ (- 24 + 24) + k ^ (-36 + 36)

τ = 0

.d) P = 24i-8j + 9k

Let's change the sign of strength

F = -24i + 8j-9k

Tae = (I j k 24 -8 9 -24 8 -9)

Tae = i ^ (72 -72) + j ^ (- 216 + 216) + k ^ (192-192)

Tae = 0

8 0

3 years ago

When we do dimensional analysis, we do something analogous to stoichiometry, but with multiplying instead of adding. Consider th

Ksivusya [100]

Answer:

The dimension is $D = L ^{2} T^{-1}$

Explanation:

From the question we are told that

$J = -D \frac{dn}{dx}$

Here $[J] = \frac{1}{L^2 T}$

$[n] =\frac{1}{L^3}$

$[x] = L$

$\frac{1}{L^2 T} = -D \frac{d(\frac{1}{L^3})}{d[L]}$

Given that the dimension represent the unites of n and x then the differential will not effect on them

$\frac{1}{L^2 T} = -D \frac{(\frac{1}{L^3})}{[L]}$

=> $D = \frac{L^{-2} T^{-1} * L }{L^{-3}}$

=> $D = L ^{2} T^{-1}$

5 0

3 years ago

Describe what happens when divergent plates move away from each other

fenix001 [56]

Answer:

they break

Explanation:

6 0

3 years ago

PLEASE HELP THE question on picture

Gnoma [55]

Vertical:

(20 m/s) sin(25º) ≈ 8.45 m/s

Horizontal:

(20 m/s) cos(25º) ≈ 18.1 m/s

7 0

3 years ago

The wavelength of red helium-neon laser light in air is 632.8 nm.

e-lub [12.9K]

(a) $4.74\cdot 10^14 Hz$

The frequency of an electromagnetic wave is given by:

$f=\frac{c}{\lambda}$

where

$c=3.0\cdot 10^8 m/s$ is the speed of the wave in a vacuum (speed of light)

$\lambda$ is the wavelength

In this problem, we have laser light with wavelength

$\lambda=632.8 nm=6.33\cdot 10^{-7} m$ . Substituting into the formula, we find its frequency:

$f=\frac{3.0\cdot 10^8 m/s}{6.33\cdot 10^{-7} m}=4.74\cdot 10^14 Hz$

(b) 427.6 nm

The wavelength of an electromagnetic wave in a medium is given by:

$\lambda=\frac{\lambda_0}{n}$

where

$\lambda_0$ is the original wavelength in a vacuum (approximately equal to that in air)

$n$ is the index of refraction of the medium

In this problem, we have

$\lambda_0=632.8 nm$

n = 1.48 (index of refraction of glass)

Substituting into the formula,

$\lambda=\frac{632.8 nm}{1.48}=427.6 nm$

(c) $2.03\cdot 10^8 m/s$

The speed of an electromagnetic wave in a medium is

$v=\frac{c}{n}$

where c is the speed of light in a vacuum and n is the refractive index of the medium.

Since in this problem n=1.48, we find

$v=\frac{3\cdot 10^8 m/s}{1.48}=2.03\cdot 10^8 m/s$

3 0

4 years ago

the electric charge remains at rest in a. static electricity, b. current electricity, c. none of these​

the electric charge remains at rest in a. static electricity, b. current electricity, c. none of these