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Masteriza [31]
3 years ago
14

the electric charge remains at rest in a. static electricity, b. current electricity, c. none of these​

Physics
1 answer:
Arturiano [62]3 years ago
6 0

Answer:

Option (a) is correct.

Explanation:

The electric charge is the inherent property of matter which appears due to the deficiency of charge or the excess number of electrons.

There are two types of charges, positive and negative.

When an object has deficiency of charge it becomes positive charge and when it gains some electrons, it becomes negative charge.

When the charge is in motion, it is called electric current and when the charge is at rest, it is called static current.

A charge at rest contributes the electric field only while the charge is in motion contributes the electric and magnetic field both.

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A 4kg block moving right at 6 m/s collides elastically with a 2kg block moving right at 3 m/s find their final velocity
nignag [31]

The final velocity of block 1 is 2.2m/s and the final velocity of block 2 is 3.4m/s.

<h3>What do you mean by elastically?</h3>

Although the terms scalability and elasticity are occasionally used interchangeably, scalability is more commonly used to describe a system's ability to successfully handle an increasing workload, while elasticity implies that the system is also capable of rapidly expanding or decreasing capacity and services. The capacity of an IT environment to grow and shrink in response to business requirements is one of its characteristics. Physics defines resilience as a material's ability to absorb energy and react elastically in order to maintain its integrity and avoid deforming as a result of the pressures it is subjected to.

To learn more about elastically, Visit:

brainly.com/question/24291236

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6 0
2 years ago
On a wave, the distance between two points that have identical status is termed by ______
Sedaia [141]
D wavelength

velocity deals w/ speed
frequency/amplitude deals with sound
5 0
3 years ago
Read 2 more answers
A 0.26 kg rod of length 80 cm is suspended by a frictionless pivot at one end. It is held horizontal and released.
Daniel [21]

Answer:

a) a_{center} = 7.38 ~m/s^2

b) a_{end} = 14.77 ~m/s^2

c) v_{center} = 2.43~m/s

Explanation:

a) Immediately after the rod is released, <u>the rod is still horizontal but now subject to gravity.</u> Since one end of the rod is fixed, then the weight of the rod applies a torque. Then by Newton's Second Law, the acceleration can be found.

\tau =I\alpha

where I is the moment of inertia of the rod with respect to its fixed end, and α is the angular acceleration.

The net torque of the rod is

\vec{\tau} = \vec{r} \times \vec{F}\\\tau = rF\sin(90) = rF

where r is the distance from center of the mass to the fixed end, so r = 0.4 m.

The weight of the rod is w = mg = 0.26 x 9.8 = 2.54 N.

So the net torque is τ = 1.01 Nm.

The moment of inertia of the rod is

I = \frac{1}{3}mL^2 = \frac{1}{3}(0.26)(0.8)^2 = 0.055~kg m^2

So, the Newton's Second Law yields

\tau = I\alpha\\\alpha = \frac{\tau}{I} = \frac{1.01}{0.055} = 18.47

<u>The relation between angular acceleration and linear acceleration is a = αr </u>

So, the linear acceleration of the rod is

a = \alpha r = 7.38~m/s^2

b) Using the same relationship between angular acceleration and linear acceleration, the linear acceleration of the end of the rod can be found.

a = \alpha L = 14.77~m/s^2

c) The conservation of energy can be used to find the velocity when the rod is vertical.

K_1 + U_1 = K_2 + U_2\\0 + mg(L/2) = \frac{1}{2}I\omega^2 + 0\\(0.26)(9.8)(0.4) = \frac{1}{2}(0.055)\omega^2\\\omega = 6.08~rad/s

The linear velocity is v = ωr, so

v = 2.43 m/s.

4 0
3 years ago
What is the solar process that results in the production of energy?
AleksandrR [38]
"solar-powered photovoltaic (PVC) panels convert the suns rays into electricity by exciting electrons in silicon cells using the photons of light from the sun. This electricity can then be used to supply renewable energy to your home or business."

I hope this helps ^-^
5 0
4 years ago
Read 2 more answers
A thin, circular hoop with a radius of 0.22 m is hanging from its rim on a nail. When pulled to the side and released, the hoop
Alex73 [517]

Answer:

Period of oscillation = 1.33 seconds

Explanation:

The period of oscillation is given by:

T = 2π√[I/(MgL)] 

for I = 2MR² and L = R,

Given: L = 0.22m = R

T = 2π√[2R/g] 

T = 2 × 3.142 Sqrt[( 2 × 0.22)/ 9.8]

T = 6.284 Sqrt(0.44/9.8)

T = 6.284 Sqrt(0.0449)

T = 6.284 × 0.2119

T = 1.33 sec

6 0
4 years ago
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