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3 years ago

How does a roller coaster get from beginning to end?

1 answer:

8 0

So it gets pushed or shot out onto the track and then the rails pull it up hills so it can cat momentum, of have that new special thingy where it shoots you forwards like a gun, and then it goes to the end.

This answer probably isn't 100% correct, and I'm sorry for that.

<em>Have a luvely day!</em>

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Djfjdbsjajajsjxjxjfjff

jek_recluse [69]

Answer:

HII CAN I HAVE BRAINLIST PLEASE I NEED ONE MORE

Explanation:

5 0

3 years ago

A 2.2-m-long steel rod must not stretch more than 1.2 mm when it is subjected to a 8.5-kN tension force. Knowing that E = 200 GP

kodGreya [7K]

Answer:

a) 0.00996 m

b) 109090909 Pa

Explanation:

Unit conversions:

$E = 200GPa = 200\times10^9 Pa$

1.2 mm = 0.0012 m

8.5 kN = 8500 N

If the 2.2m rod cannot stretch more than 0.0012 m, its maximum strain is

$\epsilon = \frac{\Delta L}{L} = \frac{0.0012}{2.2} = 0.000545455$

With elastic modulus being E = 200 GPa, then its maximum stress must be

$\sigma = E\epsilon = 200\times10^9*0.000545455 = 109090909 Pa$

Knowing the tension force being F = 8500 N, we can calculate the appropriate cross section area

$A = \frac{F}{\sigma} = \frac{8500}{109090909} = 7.79\times10^{-5}m^2$

And its corresponding diameter is

$A = \pi d^2/4$

$7.79\times10^{-5} = \pi d^2/4$

$d^2 = \frac{4*7.79\times10^{-5}}{\pi} = 9.92\times10^{-5}$

$d = \sqrt{9.92\times10^{-5}} = 0.00996 m \approx 1 cm$

7 0

3 years ago

You are pulling a sled using a horizontal rèpe, as shown in the diagram. The rope pulls the sled. exerting a force of 50 N to th

geniusboy [140]

Answer:

Part 1

20 N

Part 2

0.4 m/s²

Part 3

4 m/s

Explanation:

The force which pulls the sled right = 50 N

The friction force exterted towards left by the snow = -30 N

The mass of the sled = 50 kg

Part 1

The sum of the forces on the sled, F = 50 N + (-30) N = 20 N

Part 2

The acceleration of the sled is given as follows;

F = m·a

Where;

m = The mass of the sled

a = The accelertion

a = F/m

∴ a = (20 N)/(50 kg) = 0.4 m/s²

The acceleration of the sled, a = 0.4 m/s²

Part 3

The initial velocity of the sled, u = 2 m/s

The kinematic equation of motion to determine the speed of the sled is v = u + a·t

The speed, <em>v</em>, of the sled after t = 5 seconds is therefore;

v = 2 m/s + 0.4 m/s² × 5 s = 4 m/s.

7 0

3 years ago

A bird flies from the South Pole to the North Pole.part of the journey is 1,000 miles that takes 2 weeks,what is the birds veloc

avanturin [10]

1000 miles = 1 609 340 m
2 weeks = 1209 600 s
v = 1609340/1209600 = 1.33 m/s

7 0

3 years ago

The elements most likely for form more than one type of ion are the

bezimeni [28]

B. Transition Metals.
Hope it helps!

7 0

3 years ago