Answer:
Net force: 20 N to the right
mass of the bag: 20.489 kg
acceleration: 0.976 m/s^2
Explanation:
Since the normal force and the weight are equal in magnitude but opposite in direction, they add up to zero in the vertical direction. In the horizontal direction, the 195 N tension to the right minus the 175 force of friction to the left render a net force towards the right of magnitude:
195 N - 175 N = 20 N
So net force on the bag is 20 N to the right.
The mass of the bag can be found using the value of the weight force: 201 N:
mass = Weight/g = 201 / 9.81 = 20.489 kg
and the acceleration of the bag can be found as the net force divided by the mass we just found:
acceleration = 20 N / 20.489 kg = 0.976 m/s^2
Answer:
13807.2 J/g°C
Explanation:
I just took the test and got it correct
Answer:
c. from south to north
Explanation:
since we know that:
F = qv×B
where F is the force and in this case is pointed upward
where v is the velocity due east
the field must be due north by the right hand rule
Therefore, near the equator the magnetic field lines of the earth are directed north from south
29 million are type 2, that would be about 9.5 percent. :)
