What is the answer A,B,C,D

Which of the following are reactants in the equation below? Select all that apply.

Paha777 [63]

Answer:

Zinc, copper sulfate

Explanation:

The reactants are the ones on the left side

8 0

3 years ago

At 98.66 kPa and 20 degrees C nitrogen has a solubility in water of .018 g/L. At 82.66 kPa and 20 degrees C, it’s solubility is

forsale [732]

Yes it’s corrrct I swear

6 0

4 years ago

for the substituted cyclohexane compound shown, identify the atoms that are trans to the bromo substituent.

hodyreva [135]

Substituents are trans to each other if the appear on opposite sides in the structure. C, E, G, H and K are trans to the bromo substituent.

The substituted cyclohexane compound is shown in the image attached. Two substituents in a compound are trans to each other if they appear on opposite sides of the structure. Cis substituents appear on the same side of the structure.

Considering the structure as shown in the image attached, the substituents that are trans to the bromo substituent are the substituents shown as letters C, E, G, H and K. They lie opposite to the bromo substituent.

Learn more: brainly.com/question/8155254

6 0

3 years ago

How much ice (in grams) would have to melt to lower the temperature of 353 mL of water from 26 ∘C to 6 ∘C? (Assume the density o

Rashid [163]

Answer:

The mass of ice required to melt to lower the temperature of 353 mL of water from 26 ⁰C to 6 ⁰C is 85.4197 kg

Explanation:

Heat gain by ice = Heat lost by water

Thus,

Heat of fusion + $m_{ice}\times C_{ice}\times (T_f-T_i)=-m_{water}\times C_{water}\times (T_f-T_i)$

Where, negative sign signifies heat loss

Or,

Heat of fusion + $m_{ice}\times C_{ice}\times (T_f-T_i)=m_{water}\times C_{water}\times (T_i-T_f)$

Heat of fusion = 334 J/g

Heat of fusion of ice with mass x = 334x J/g

For ice:

Mass = x g

Initial temperature = 0 °C

Final temperature = 6 °C

Specific heat of ice = 1.996 J/g°C

For water:

Volume = 353 mL

$Density (\rho)=\frac{Mass(m)}{Volume(V)}$

Density of water = 1.0 g/mL

So, mass of water = 353 g

Initial temperature = 26 °C

Final temperature = 6 °C

Specific heat of water = 4.186 J/g°C

So,

$334x+x\times 1.996\times (6-0)=353\times 4.186\times (26-6)$

$334x+x\times 11.976=29553.16$

345.976x = 29553.16

x = 85.4197 kg

Thus,

<u>The mass of ice required to melt to lower the temperature of 353 mL of water from 26 ⁰C to 6 ⁰C is 85.4197 kg</u>

7 0

4 years ago

If an automobile air bag has a volume of 11.6 ll , what mass of nan3nan3 (in gg ) is required to fully inflate the air bag upon

Tresset [83]

22.3 g of NaN₃ are required to fully inflate an airbag of 11.6 L at STP.

To find the mass, the given data was,

Volume = 11.6 Liters

<h3>What is decomposition reaction?</h3>

A decomposition reaction can be defined as a chemical reaction in which one reactant breaks down into two or more products.

In airbags, sodium azide decomposes to form sodium and nitrogen gas, which inflates the bag. The decomposition reaction is:

2 NaN₃ ⇒ 2 Na + 3 N₂

We can calculate the mass of NaN₃ needed to produce 11.6 L of N₂ at STP, using the following relations.

At STP, 1 mole of N₂ occupies 22.4 L.
The molar ratio of N₂ to NaN₃ is 3:2.
The molar mass of NaN₃ is 65.01 g/mol.

Substituting all the known values to find the volume,

11.6 × ( 1 / 22.4) × ( 2/3) × ( 65.01 / 1)

= 22.4 g.

22.4 g of NaN₃ are required to fully inflate an airbag of 11.6 L at STP.

Learn more about decomposition reaction,

brainly.com/question/8009068

#SPJ4

5 0

2 years ago