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Scorpion4ik [409]
3 years ago
9

A perpetual motion machine can never be built because it is not possible to eliminate

Physics
1 answer:
d1i1m1o1n [39]3 years ago
8 0

Answer:

D. Friction

Explanation:

Friction is a force that opposes motion. So a perpetual motion machine can never be built because it is impossible to eliminate frictional force. It can only be reduced

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What is required for an electric charge to flow through a wire?
Nataly [62]

Answer:

AN electric current is required for  an electric charge

Explanation:

7 0
3 years ago
A paper filled capacitor is charged to a potential difference of 2.1 V and then disconnected from the charging circuit. The diel
Goryan [66]

Answer:

Part a)

V' = 7.77 Volts

Part b)

k' = 6.27

Explanation:

As we know that capacitor plate is connected across 2.1 V and after charging it is disconnected from the battery

So here we can say that charge on the plates will remain conserved

So we will have

Q = kC(2.1)

now dielectric is removed between the plates of capacitor

so new potential difference between the plates

V' = \frac{Q}{C'}

V' = \frac{kC(2.1)}{C}

V' = 3.7 \times 2.1

V' = 7.77 Volts

Part b)

Now the capacitor plates are again isolated and unknown dielectric is inserted between the plates

So again charge is same so potential difference is given as

V" = \frac{Q}{k'C}

0.59 V = \frac{kCV}{k'C}

0.59 = \frac{3.7}{k'}

k' = 6.27

5 0
3 years ago
How many calories are needed to raise the temperature of 2g of water 3 C?
olga nikolaevna [1]

Answer:

The number of calories needed is 6c.

Explanation:

The amount of energy Q needed to raise the temperature \Delta T of water of mass m is

Q = mC\Delta T

where C = 1cal/g\cdot C is the specific heat capacity of water.

Putting in numbers into equation (1), we get:

Q = (2g)(1)(3^oC )\\

\boxed{Q = 6\:cal }

which is the number of calories needed.

8 0
3 years ago
Exactly one turn of a flexible rope with mass m is wrapped around a uniform cylinder with mass M and radius R.
Dennis_Churaev [7]

Answer:

\omega=\sqrt{\omega_0^2(\frac{M+m}{M})}

Explanation:

The rotational kinetic energy when the cylinder is with the rope is:

E_k=\frac{1}{2}I_c\omega_0^2+\frac{1}{2}I_r\omega_0^2

where we used the fact that both rope and cylinder hast the same w. This E_k must conserve, that is, E_k must equal E_k when the rope leaves the cylinder. Hence, the final w is given by:

E_{k1}=E_{k2}\\\\\frac{1}{2}I_c\omega_0^2+\frac{1}{2}I_r\omega_0^{2}=\frac{1}{2}I_c\omega^2\\\\\omega=\sqrt{\omega_0^2(\frac{I_c+I_r}{I_c})} (1)

For Ic and Ir we can assume that the rope is a ring of the same radius of the cylinder. Then, we have:

I_c=\frac{1}{2}MR^2\\\\I_r=mR^2

Finally, by replacing in (1):

\omega=\sqrt{\omega_0^2(\frac{M+m}{M})}

hope this helps!!

7 0
2 years ago
In which type of bone does ossification occur in the membranes?
Afina-wow [57]
In the formation of flat bones such as the skull the mandibles and the clavicles  
3 0
3 years ago
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