Answer:
Ka3 for the triprotic acid is 7.69*10^-11
Explanation:
Step 1: Data given
Ka1 = 0.0053
Ka2 = 1.5 * 10^-7
pH at the second equivalence point = 8.469
Step 2: Calculate Ka3
pKa = -log (Ka2) = 6.824
The pH at the second equivalence point (8.469) will be the average of pKa2 and pKa3. So,
8.469 = (6.824 + pKa3) / 2
pKa3 = 10.114
Ka3 = 10^-10.114 = 7.69*10^-11
Ka3 for the triprotic acid is 7.69*10^-11
With a pH of 2, it's very acidic and far from a neutral pH and basic. I would say chemical as my answer.
Commercial agriculture can often lead to water-quality problems in the following ways:
- The washing of fertilizers and pesticides into water bodies from farms.
<h3>What is water quality?</h3>
Water quality refers to the state of a water body that encompasses it's physical, chemical and biological characteristics.
The water quality of a water body is crucial to its suitability for domestic or drinking purpose.
Commercial agriculture greatly affects water quality in the following ways:
- The washing of fertilizers and pesticides into water bodies from farms.
Learn more about water quality at: brainly.com/question/20848502
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Well we need to see the fossil
Answer:
That means that if you are calculating entropy change, you must multiply the enthalpy change value by 1000. So if, say, you have an enthalpy change of -92.2 kJ mol-1, the value you must put into the equation is -92200 J mol-1
