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OlgaM077 [116]
2 years ago
11

Which of the following would be most useful in trying to obtain procedural information to replicate an experiment previously pub

lished?
Chemistry
1 answer:
Anit [1.1K]2 years ago
4 0

Answer:

Peer-reviewed Journal Article

Explanation:

1.Dictionary

2.Encyclopidia

3.Internet Search Engine

4.Peer-reviewed Journal Article

The correct answer as to which would be most useful in trying to obtain procedural information to replicate an experiment previously published would be <u>a peer-reviewed journal article</u>.

<em>A peer-reviewed journal article is a journal article written by an expert or experts on a particular topic and has undergone thorough reviews by experts in the same field and certified to be of good-enough standards to be published. </em>

<u>Such an article would contain all the necessary information relating to the experiment leading to the article</u>. Hence, in order to obtain procedural information to replicate an experiment that has been previously published, a peer-reviewed journal published on the same topic would do be the right place to seek.

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Answer:

(1760 ÷ 64) x 24.4 =671dm^3

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3 years ago
If one mole of a substance has a mass of 56.0 g, what is the mass of 11 nanomoles of the substance? Express your answer in nanog
9966 [12]

Answer:

616,0 ng is the right answer.

Explanation:

You should know that 1 mole = 1 .10^9 nanomoles

Get the rule of three.

1 .10^9 nanomoles ...................... 56.0 gr

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8 0
3 years ago
C12H26O + SO3+NaOH ----&gt; C12H25NaSO4+ H2O
Vlad [161]

Answer:

We can solve this by the method of which i solved your one question earlier

so again here molar mass of C12H25NaSO4 is 288.372 and number of moles for 11900 gm of C12H25NaSO4 will be = 11900/288.372

which is almost = 41.26 moles

so to get one mole of C12H25NaSO4 we need one mole of C12H26O

so for 41.26 moles of C12H25NaSO4 it will require 41 26 moles of C12H26O

so the mass of C12H26O = 41.26× its molar mass

C12H26O = 41.26×186.34

= 7688.38 gm!!

so the conclusion is If you need 11900 g of C12H25NaSO4 (Sodium Lauryl Sulfate) you need C12H26O 7688.38 gm !!

Again i d k wether it's right or wrong but i tried my best hope it helped you!!

4 0
3 years ago
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kupik [55]

Answer:

c) Both a) and b)

Explanation:

please mark me brainliest

6 0
2 years ago
Read 2 more answers
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