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andreyandreev [35.5K]
3 years ago
5

W Find the quotient. 6,219.8 = 1,000

Chemistry
1 answer:
professor190 [17]3 years ago
7 0
IM NOT A BOT but u should use miniwebtool.com yea
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What element has 1 energy level and 2 valence electrons
Anvisha [2.4K]

Answer: Hydrogen and helium

Explanation:

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3 years ago
Which of the following precautions is important when using a Bunsen burner or Meker burner?a. Set up your work space so that wir
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Answer:

Never leave an open flame unattended

Explanation: if an open flame is left unattended it can cause a fire outbreak so we have to watch it at all times to prevent the fire outbreak

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4 years ago
Which part of the amino acid helps identify features that differentiate one amino acid from another
Natasha_Volkova [10]
The part of the amino acid which helps to identify features that differentiate one amino acid from another is the SIDE CHAIN OF EACH AMINO ACID.
Amino acids are made up of five basic parts, these are:
1. A central carbon atom
2. A hydrogen atom
3. An amino group
4. A carboxyl group and 
5. A R group, also known as a side chain.
The side chain distinguishes one amino acid from the other; different amino acids have different side chains.
6 0
3 years ago
Describe the relationship between"q" and energy in the melting of an ice cube.
klio [65]

Answer:

Now "q" is  the heat and energy is the capacity of any object or body ton perform any work. So we can relate them if we take the term specific heat in consideration.

As specific heat is the the amount of heat required to raise the temperature of an object in specific from one degree Celsius, for ice it is 2.108 kJ/kgK.

Explanation:

  • c = specific heat capacity,

  • q = heat

  • ΔT = change in temperature

So, we have:

  • C= Q/ΔT
  • It is the ratio of the amount of heat energy transferred to an object to the resulting increase in temperature of the object.

4 0
4 years ago
At 311 K, this reaction has a K c value of 0.0111 . X ( g ) + 2 Y ( g ) − ⇀ ↽ − 2 Z ( g ) Calculate K p at 311 K. Note that the
Aleks [24]

Answer:

K_{p}=4.35\times 10^{-4}

Explanation:

We know, K_{p}=K_{c}(RT)^{\Delta n}

where, R = 0.0821 L.atm/(mol.K), T is temperature in kelvin and \Delta n is difference in sum of stoichiometric coefficient of products and reactants

Here \Delta n=(2)-(2+1)=-1 and T = 311 K

So, K_{p}=(0.0111)\times [(0.0821L.atm.mol^{-1}.K^{-1})\times 311K]^{-1}=4.35\times 10^{-4}

Hence value of equilibrium constant in terms of partial pressure (K_{p}) is 4.35\times 10^{-4}

4 0
3 years ago
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