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In-s [12.5K]
2 years ago
14

What are autotrophs? Name three types of organisms that are autotrophs.

Physics
1 answer:
ValentinkaMS [17]2 years ago
4 0
Autotrophs are organisms that can make its own food by synthesizing organic nutrients from inorganic materials. Three types include: photoautotrophs, chemoautotrophs, and plants.
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What is the term for an area of a country located away from capital?
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Province. Is what is located away from the capital.
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3 years ago
Why does th ground and atmosphere get warm during the day
Tcecarenko [31]

Answer:

The Greenhouse Effect Revisited. When solar energy strikes the planet during the day, the ground, highways and other objects get hot and absorb that energy. As the sun goes down, the Earth cools by giving off infrared radiation. Because greenhouse gases absorb part of this radiation, the atmosphere warms and keeps the Earth from getting too cold.

6 0
3 years ago
A bird flies 3.6 km due west and then 1.8 km due north. Another bird flies 1.8 km due west and 3.6 km due north. What is the ang
kondor19780726 [428]
Define unit vectors as follows:
\hat{i} is in the eastern direction.
\hat{j} is in the northern direction.

The position of the first bird is
\vec{a} = -3.6 \, \hat{i} + 1.8 \, \hat{j}

The position of the second bird is
\vec{b} = - 1.8 \, \hat{i} + 3.6 \, \hat{j}

Let θ = the angle between the net displacement vector for the two birds.
By definition,
\vec{a} . \vec{b} = |a| |b| cos\theta \\\\ \theta = cos^{-1} ( \frac{\vec{a}.\vec{b}}{|a||b|} )

\vec{a}.\vec{b} = (-3.6)(-1.8)+(3.6)(1.8) = 12.96
|a| =  \sqrt{3.24+12.96} =4.025
Similarly,
|b| = 4.025

Therefore
\theta = cos^{-1}  \frac{12.96}{4.025^{2}} =36.9^{o}

Answer:  36.9°
5 0
3 years ago
You are asked to explain what happens to individual atoms when a chemical change takes place in lab you are doing in class. What
ss7ja [257]

B. They are rearranged.

The First Law of Thermodynamics states that matter and energy can not be created or destroyed.

3 0
3 years ago
Read 2 more answers
Determine the vector perpendicular to the plane of A= 31+ 6j - 2k and B=4i-j +3k
Sliva [168]

The vector perpendicular to the plane of A = 3i+ 6j - 2k and B = 4i-j +3k is 16 i - 17 j - 27 k

Let r be the vector perpendicular to A and B,

r = A * B

A = 3i + 6j - 2k

B = 4i - j + 3k

a1 = 3

a2 = 6

a3 = - 2

b1 = 4

b2 = - 1

b3 = 3

a * b = ( a2 b3 - b2 a3 ) i + ( a3 b1 - b3 a1 ) j + ( a1 b2 - b1 a2 ) k

a * b = [ ( 6 * 3 ) - ( - 1 * - 2 ) ] i + [ ( - 2 * 4 ) - ( 3 * 3 ) ] j + [ ( 3 * - 1 ) - ( 4 * 6 ) ] k

a * b = 16 i - 17 j - 27 k

The perpendicular vector, r = 16 i - 17 j - 27 k

Therefore, the vector perpendicular to the plane of A = 3i + 6j - 2k and B = 4i - j + 3k is 16 i - 17 j - 27 k

To know more about perpendicular vectors

brainly.com/question/14384780

#SPJ1

5 0
1 year ago
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