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Oksanka [162]
3 years ago
7

How will doctors most likely respond to someone who has an active case of drug-resistant tuberculosis?

Physics
1 answer:
ikadub [295]3 years ago
6 0

Answer.

Doctors will still use other drugs that are known to treat tuberculosis, even if they are less effective than the common drugs

Explanation:

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Isotopes describes atoms with different atomic masses due to varying numbers of neutrons
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. Consider a fully extended arm that is rotating about the shoulder such that with a shoulder-to-hand length of 30 cm. If the ar
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Answer:

13.309 m/s²

Explanation:

Length from shoulder to hand, l = 30 cm = 0.3 m

initial velocity, u = 1 m/s

final velocity, v = 2.5 m/s

time, t = 3 s

Let the tangential acceleration is a.

by using first equation of motion

v = u + at

2.5 = 1 + 3 a

a = 0.5 m/s²

Let the centripetal acceleration is a'.

a' = v'²/l

a' = 2 x 2 / 0.3

a' = 13.3 m/s²

The tangential acceleration and the centripetal acceleration are both perpendicular to each other. So, the net acceleration is given by

A=\sqrt{a^{2}+a'^{2}}

A=\sqrt{0.5^{2}+13.3^{2}}

A = 13.309 m/s²

3 0
4 years ago
Vector a cross b whole square<br><br>​
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Answer:

Kriss go Brrrrrrrrrrr

Explanation:

4 0
3 years ago
Name two things that reduce friction
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<span>Make the surfaces smoother. Rough surfaces produce more friction and smooth surfaces reduce friction. ...Lubrication is another way to make a surface smoother. ...Make the object more streamlined. ...Reduce the forces acting on the surfaces. ...<span>Reduce the contact between the surfaces.

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A slender rod is 80.0 cm long and has mass 0.390 kg . A small 0.0200-kg sphere is welded to one end of the rod, and a small 0.05
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Answer:

v = 1.08 m/s

Explanation:

What is the linear speed of the 0.0500-kg sphere as its passes through its lowest point?

The decrease in PE is

d = 80.0cm * 1 / 1000m = 0.80m

h = 0.80 m /2 = 0.40 m

ΔPE = m*g*h

ΔPE = (0.0500 - 0.0200)kg * 9.8m/s² * 0.400 m

ΔPE = 0.1176 J

The moment of inertia of the assembly is

I = 1/12*m*L² + (m1 + m2)*(L/2)²

I = 1/12*0.390kg*(0.800m)² + 0.0700kg*(0.400m)²

I = 0.032 kg·m²

KE = ½Iω²

0.1176 J = ½ * 0.032kg·m² * ω²

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