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DiKsa [7]
3 years ago
6

Laquite wants to toss a tennis ball straight up to Michele who is 5 meters above her. If the wants the ball to stop just as it r

eaches Michele, how fast should she toss the ball?
Physics
1 answer:
baherus [9]3 years ago
5 0

Answer:

The initial speed of the tennis ball is 9.89 m/s.

Explanation:

Given that,

Laquite wants to toss a tennis ball straight up to Michele who is 5 meters above her. Final speed of the ball is should be 0. We need to find the initial velocity of the ball. It can be calculated using the conservation of energy as :

u=\sqrt{2gh} \\\\u=\sqrt{2\times 9.8\times 5} \\\\u=9.89\ m/s

So, the initial speed of the tennis ball is 9.89 m/s. Hence, this is the required solution.

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Brilliant_brown [7]
V=at and a=F/m

140/.070 = 2000m/s^2

2000*.020 = 40m/s

The ball’s velocity increased by 40m/s.
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2) A motorcycle is moving at a constant speed of 40 km/h. How long does it take the motorcycle to
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2 hours

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3 years ago
A firecracker in a coconut blows the coconut into three pieces. Twopieces of equal mass fly off south and west, perpendicular to
loris [4]

Answer:

V = 13m/s

North-East (i.e. 45 degree from North)

Explanation:

This question deals with the idea of momentum.

Since the directions of a compass are fixed, we can take south as horizontal and west as vertical. Since both pieces of coconut are of equal mass, then the resultant of the two pieces would be in between South and West and the third piece would be opposite this direction and be in the North-East (i.e. 45 degree from North) direction

To find the speed of the third piece, we first find the speed on the two pieces of the coconut in terms of V_{x} (horizontal component of velocity) and V_{y} (vertical component of velocity)

We have

V_{y} = Velocity in South direction = 18m/s

m_{y} = Mass of piece in South direction = m

V_{x} = Velocity in West direction = 18m/s

m_{x} = Mass of piece in West direction = m

V_{ry} = Velocity of Third Piece in North direction = unknown

V_{rx} = Velocity of Third Piece in East direction = unknown

m = Mass of third piece = 2m

mV_{ry}  = m_{y} V_{y} \\ 2mV_{ry}  = m18\\ V_{ry} = 9

mV_{rx}  = m_{x} V_{x} \\ 2mV_{rx}  = m18\\ V_{rx} = 9

Since we now know the horizontal and vertical component of the velocity of the third piece of coconut we find the resultant velocity. Since we know the direction is North-East, we can imagine a right angled triangle with base of 9 and height 9 and the hypotenuse equal to the resultant velocity .

We can simply apply the Pythagoras theorem and find the hypotenuse

Hypotenuse^{2}  = Height^{2}  + Base^{2} \\ V_{3}^2  = 9^{2} + 9^{2} \\ V = 12.728 m/s

V = 13m/s

6 0
3 years ago
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