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2 years ago

What are the conditions of equilibrum

Physics

2 answers:

horsena [70]2 years ago

6 0

Answer:

Forgive me if am wrong but the conditions are

The lines of action are coplanar (in the same plane)

The lines of action are convergent (they cross at the same point)

The vector sum of these forces is equal to the zero vector.

natta225 [31]2 years ago

3 0

Answer:

they are given below

The sum or resultant of all external forces acting on the body must be equal to zero.

The sum or resultant of all external torques from external forces acting on the object must be zero.

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The mass of a planet is 3.7 x 1024 kg. If the planet has a radius of 9.2 x 106 m what is the acceleration of gravity for a perso

nalin [4]

Explanation:

It s given that,

Mass of a planet, $M=3.7\times 10^{24}\ kg$

Radius of a planet, $R=9.2\times 10^{6}\ m$

(1) We need to find the acceleration due to gravity for a person on the surface of the planet. Its formula is given by :

$g=\dfrac{GM}{R^2}$

$g=\dfrac{6.67\times 10^{-11}\ Nm^2/kg^2\times 3.7\times 10^{24}\ kg}{(9.2\times 10^{6}\ m)^2}$

$g=2.91\ m/s^2$

(2) The escape velocity is given by :

$v=\sqrt{\dfrac{2GM}{R}}$

$v=\sqrt{{\dfrac{2\times 6.67\times 10^{-11}\ Nm^2/kg^2\times 3.7\times 10^{24}\ kg}{9.2\times 10^{6}\ m}}$

v = 7324.61 m/s

Hence, this is the required solution.

3 0

2 years ago

An AC adapter for a telephone answering machine uses a transformer to reduce the line voltage of 120 V to a voltage of 5.00 V. T

Maksim231197 [3]

Answer:

Explanation:

We are given that

Initial voltage, $V_1=120 V$

Final voltage, $V_2=5 V$

Number of tuns in primary coil of the transformer, $N_p=840$

Rms current, $I_{rms}=580mA=580\times 10^{-3} A$

$1 mA=10^{-3} A$

We have to find the number of turns are there on the secondary coil.

We know that

$\frac{N_s}{N_p}=\frac{V_2}{V_1}$

Using the formula

$\frac{N_s}{840}=\frac{5}{120}$

$N_s=\frac{5}{120}\times 840=35$

Hence, there are number of turns on the secondary coil=35

8 0

2 years ago

Two charged objects have a repulsive force of .80 N. If the charge of one of the objects is doubled, then what is the new force?

sveticcg [70]

The new force would be 1.6 N.
Since the charges multiply as variables (q1)x(q2), then it would simply be double (q1)x(q2), or 1.6.

6 0

2 years ago

Answer:

Arlecino [84]

Answer:

A) Diagonals of a parallelogram bisect each other

6 0

3 years ago

An object begins x=75.2 m and undergoes a displacement of -48.7 m. what is its final position?

xz_007 [3.2K]

Answer:

26.5 m

Explanation:

$x_{o}$ = initial position of the object = 75.2 m

$x$ = final position of the object

$d$ = displacement of the object = - 48.7

Displacement of the object is given as the difference of final and initial position of the object

$d = x - x_{o}$

Inserting the values

- 48.7 = x - 75.2

x = 26.5 m

8 0

2 years ago