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3 years ago

What are the conditions of equilibrum

Physics

2 answers:

horsena [70]3 years ago

6 0

Answer:

Forgive me if am wrong but the conditions are

The lines of action are coplanar (in the same plane)

The lines of action are convergent (they cross at the same point)

The vector sum of these forces is equal to the zero vector.

natta225 [31]3 years ago

3 0

Answer:

they are given below

The sum or resultant of all external forces acting on the body must be equal to zero.

The sum or resultant of all external torques from external forces acting on the object must be zero.

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What body parts were scientists wanting to image that prompted the development of the CT scanner

zalisa [80]

Answer:

The head

Explanation:

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3 years ago

A 0.20-kg object is attached to the end of an ideal horizontal spring that has a spring constant of 120 N/m. The simple harmonic

miss Akunina [59]

Answer:

0.07756 m

Explanation:

Given mass of object =0.20 kg

spring constant = 120 n/m

maximum speed = 1.9 m/sec

We have to find the amplitude of the motion

We know that maximum speed of the object when it is in harmonic motion is given by $v_{max}=A\omega$ where A is amplitude and $\omega$ is angular velocity

Angular velocity is given by $\omega=\sqrt{\frac{k}{m}}$ where k is spring constant and m is mass

So $v_{max}=A\sqrt{\frac{k}{m}}$

$A=V_{max}\sqrt{\frac{m}{k}}=1.9\times \sqrt{\frac{0.2}{120}}=0.07756 \ m$

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3 years ago

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Signal words most often used in a chronological essay are

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3 years ago

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Which simple machine is a doorknob?

Anestetic [448]

The answer is wheel and axle

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3 years ago

I've had several mental breakdowns please help me

sesenic [268]

Answer:

The efficiency of the system is 63.7 %

Explanation:

Given;

input power of the motor, = 1.5 kW = 1,500 W

mass of the car lifted, m = 1300 kg

height through which the car was lifted, h = 1.8 m

time, t = 24 s

The output power of the motor is calculated as;

Output Power = F x v

= (mg) x (d/t)

= (1300 x 9.8) x (1.8 / 24)

= 12,740 x 0.075

= 955.5 W

The efficiency of the system is calculated as;

$E = \frac{0utput \ power}{1nput \ power} \times \ 100\%\\\\E = \frac{955.5}{1500} \times \ 100\% \\\\E = 63.7 \ \%$

The correct answer is 63.7%

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3 years ago