How many signifficant figures do the following number have 258
1 answer:
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Well we can just use F=ma. The force is 10N, the mass is 50 kg, solve for a. Well since we kg and N, no conversion is necessary. So just plugging in the numbers, we get
10N = 50 kg · a
A newton is just
The s^2 and 50 kg you multiply
The kg's cancel and 10/50 is 1/5
So the acceleration is 1/5 m/s^2
Answer:
Explanation:
When coefficient of friction is approximately zero then we have
here we know that
R = 30 m
now when friction coefficient is 0.30 then we have
now we have
Answer:8.75 s,
136.89 m
Explanation:
Given
Initial velocity
velocity after 5 s is
Therefore acceleration during these 5 s
therefore time required to stop
v=u+at
here v=final velocity =0 m/s
initial velocity =31.29 m/s
(b)total distance traveled before stoppage
s=136.89 m