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3 years ago

The region outside the nucleus where an electron can be found

Chemistry

1 answer:

Alex Ar [27]3 years ago

6 0

The region where an electron is most likely to be is called an orbital

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How many grams of Mg are needed to produce 224 g of MgO in the complete reaction of Mg

zmey [24]

Answer:

134.4 g of Mg

Explanation:

reaction:

2Mg + O2 ➡️ 2MgO

1) find the mol of MgO

mol = mass / molar mass

mass = 224 g

molar mass = 24+16 = 40

mol = 224 / 40

= 5.6 moles

2 mol = 5.6 moles

2) find the mass of Mg

mass = mol × molar mass

mol = 5.6

molar mass = 24

mass = 5.6 × 24

= 134.4 g

7 0

3 years ago

S8 + 12 O2 → 8 SO3 How many moles of SO3 can be produced from 6 moles of O2?

MA_775_DIABLO [31]

Answer:

4 moles of SO3 will be produced from 6 moles of oxygen.

Explanation:

From the reaction given

S8 + 12 O2 ----> 8 SO3

12 moles of oxygen reacts to form 8 moles of SO3

if 6 moles of oxygen were to be used instead, it has been reduced to half of the original mole of oxygen used. Then the moles of SO3 will also be reduced to half.

6 moles of O2 will yield 4 moles of SO3

12 moles = 8 moles

6 moles = ?

? = 6 * 8 / 12

? = 48/ 12

? = 4 moles of SO3.

8 0

3 years ago

The enthalpy of fusion of solid n-butane is 4.66 kJ/mol. Calculate the energy required to melt 58.3 g of solid n-butane.

adelina 88 [10]

Answer : The energy required to melt 58.3 g of solid n-butane is, 4.66 kJ

Explanation :

First we have to calculate the moles of n-butane.

$\text{Moles of n-butane}=\frac{\text{Mass of n-butane}}{\text{Molar mass of n-butane}}$

Given:

Molar mass of n-butane = 58.12 g/mole

Mass of n-butane = 58.3 g

Now put all the given values in the above expression, we get:

$\text{Moles of n-butane}=\frac{58.3g}{58.12g/mol}=1.00mol$

Now we have to calculate the energy required.

$Q=\frac{\Delta H}{n}$

where,

Q = energy required

$\Delta H$ = enthalpy of fusion of solid n-butane = 4.66 kJ/mol

n = moles = 1.00 mol

Now put all the given values in the above expression, we get:

$Q=\frac{4.66kJ/mol}{1.00mol}=4.66kJ$

Thus, the energy required to melt 58.3 g of solid n-butane is, 4.66 kJ

7 0

3 years ago

What is the mass of 1 mole of lithium?

Korolek [52]

Answer: The mass of 1 mole of lithium is 6.941 grams.

Explanation:

To calculate the mass of a compound or element, we use the formula used to calculate the number of moles:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Where,

Number of moles of lithium = 1 mole

Given mass of lithium = ? g

Molar mass of lithium = 6.941 g/mol

Putting value in above equation, we get:

$1mole=\frac{\text{Given mass}}{6.941g/mol}\\\\\text{Mass of lithium}=6.941g$

Hence, the mass of 1 mole of lithium is 6.941 grams.

5 0

3 years ago

Read 2 more answers

Carbon monoxide prevents __________. A. the breakdown of other chemicals in the liver B. fuel from igniting at the wrong time C.

aksik [14]

Answer: C. the blood from carrying oxygen to the tissues of the body.

The carbon monoxide is a poisonous gas, it inhibits the ability of the hemoglobin to distribute oxygen. Hemoglobin is a protein in the red blood cells. The function of the hemoglobin is to distribute oxygen throughout the body. It has high affinity for oxygen. The carbon monoxide replaces oxygen in the hemoglobin. This results in respiratory and cardiac arrest.

7 0

3 years ago