Answer:
Mass of chlorine = 47.22 g
Explanation:
Given data:
Mass of sodium = 30.5 g
Mass of chlorine= ?
Solution:
Chemical equation:
2Na + Cl₂ → 2NaCl
Number of moles of Na:
Number of moles = mass/molar mass
Number of moles = 30.5g/ 23 g/mol
Number of moles = 1.33 mol
Now we will compare the moles of Cl
₂ with Na from balance chemical equation.
Na : Cl
₂
2 : 1
1.33 : 1/2×1.33 = 0.665 mol
Mass of chlorine gas:
Mass = number of moles × molar mass
Mass = 0.665 mol × 71 g/mol
Mass = 47.22 g
Answer:
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Explanation:
3.2 g KClO3
Explanation:
1.1 g C12H22O11 × (1 mol C12H22O11/342.3 g C12H22O11)
= 0.0032 mol C12H22O11
0.0032 mol C12H22O11 × (8 mol KClO3/1 mol C12H22O11)
= 0.026 mol KClO3
Therefore, the minimum amount of KClO3 needed is
0.026 mol KClO3 × (122.55 g KClO3/1 mol KClO3)
= 3.2 g KClO3
Answer:
B
Explanation:
B, Hcl + NaoH = NaCl + H2O
Water would flow into the egg through osmosis.l causing it to expand.
